If the sum of the first 10 terms of an arithmetic sequence is 235 and the sum of the second 10 terms is 735. The first term of the arithmetic sequence is -21.5 and the common difference is 10.
Let's a represent the first term of the arithmetic sequence and the common difference as d
Formula for the sum of the first n terms of an arithmetic sequence is given by:
S_n = (n/2) * [2a + (n - 1)d]
So,
Sum of the first 10 terms: S₁₀ = 235
Sum of the second 10 terms: S₂₀ = 735
First 10 terms:
S₁₀ = (10/2) * [2a + (10 - 1)d]
235 = 5 * [2a + 9d]
47 = 2a + 9d
Second 10 terms:
S₂₀ = (10/2) * [2a + (20 - 1)d]
735 = 5 * [2a + 19d]
147 = 2a + 19d
Now we have a system of equations:
2a + 9d = 47
2a + 19d = 147
(2a + 19d) - (2a + 9d) = 147 - 47
10d = 100
d = 10
Substitute it into the first equation to solve for "a":
2a + 9(10) = 47
2a + 90 = 47
2a = -43
a = -21.5
Therefore the first term of the arithmetic sequence is -21.5 and the common difference is 10.
Learn more about arithmetic sequence here:brainly.com/question/6561461
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Answer:
Step-by-step explanation:
The sum of the first 10 terms of an arithmetic sequence is:
the sum of the second 10 terms is: a₁₁ + a₁₂+...+ a₂₀
And the sum of the first 20 terms of an arithmetic sequence is:
so the sum of the second 10 terms is:
Therefore we have:
and:
B.5 / 10
C.5 / 100
D.5 / 1000"
Answer:
2 5/8 miles or 2.625 miles
Step-by-step explanation:
We are told in the question that
Linda walked 3/4 of the length of the Tremont Trail before stopping for a rest.
From the question, the length of the Tremont Trail = 3 1/2 miles
Hence, the distance (how far )Linda has walked =
3/4 of 3 1/2 miles
= 3/4 × 3 1/2 miles
= 3/4 × 7/2 miles
= 21/8 miles
= 2 5/8 miles or 2.625 miles
Therefore, Linda had walked 2 5/8 miles or 2.625 miles on the Tremont trail
Answer: the awnser is 2 5/8
Step-by-step explanation:
The question can be addressed using the principles of Normal Distribution. Given the z-chart, 8 ounces is the observed value for the 99.5th percentile, which equates to approximately 2.58 standard deviations. Therefore, the mean setting of the coffee machine should be set around 8 ounces for the cup to overflow only 0.5% of the time.
The situation described in the question is a typical case of application of Normal Distribution. As a reminder, in a Normal Distribution, 99.7% of the values lie within 3 standard deviations of the mean. The question states that the cup should overflow only 0.5% of the time. Therefore, we need to consider the 99.5% of the left side under the normal curve (as we're considering the upper limit), which corresponds to around 2.58 standard deviations under the normal curve.
Given that the standard deviation (σ) is 0.4 ounces, using the formula X = μ + Zσ (where Z is the Z-score corresponding to the desired percentile, μ is the mean we want to find, and X is the threshold value where the cup overflows at 8 ounces), we can substitute the known values and solve for μ.
Therefore, 8 = μ + 2.58 * 0.4 Solving for μ gives us around μ = 7.966, or about 8 ounces. Hence, the mean setting of the coffee machine should be set around 8 ounces to ensure that the cup will overflow only 0.5% of the time.
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Answer: -1.5 ≤ x < 9.2
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
"All real numbers": we will use the variable x to represent all the real numbers.
"All real numbers that are greater than or equal to -1.5". This means that x is greater or equal (≤) to the number 1.5.
"And less than 9.2": less is represented with the symbol <
Mathematically speaking:
-1.5 ≤ x < 9.2
Feel free to ask for more if needed or if you did not understand something.
4 is because it is greater and less than