Use the distributive property to find the value of 8(10 + 9).
152
82
89
97

Answers

Answer 1

Answer: The answer is 89 because you distribute the 8 to the 10 and then to the 9. 80+9=89

Answer 2

Answer: 152 because 8x10=80 and 8x9=72 so 80+73=152

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A rope is stretched from the top of a 60 feet pole to a point on the ground 11 feet away from the base of the pole. What is the length of the rope?

How many sides does a cylinder have

Answers

Hi, A cylinder has 3 faces - 2 circle ones and a rectangle

correct, it has 2 sides.

Amanda tells you that because a variable is in the denominator, the equation three over x plus one over three equals five over six becomes unsolvable. Amanda explains, "There is a value for x that makes the denominator zero, and you can't divide by zero." How will you show Amanda that the equation is still solvable and explain your reasoning?

Answers

For this case we have the following equation:
$(3)/(x) + (1)/(3) = (5)/(6)$
We multiply both sides of the equation by 3x:
$9 + x = (5)/(2)x$
We multiply both sides of the equation by 2:
$18+2x=5x$
From here, we clear the value of x:
$5x-2x=18 3x=18$
$x = (18)/(3)$
$x=6$
Answer:
You can not divide by zero, but you can rewrite the expression to clear x.
The value of x is given by:
$x=6$

(3 / x) + (1/3) = (5 / 6)
Taking the LCM on the left side
(9 + x)/(3x) = (5/6)
54 + 6x = 15x
From this step, it is visible that x is no longer in th denominator and even if it is 0, the equation is solvable.
9x = 54
x = 6

HELP NOW PLEASE HOW DO I FIGURE THIS OUT?

Answers

Hello,

∛72=∛(2^3*3^2)=2*∛3^2=2∛9
Answer C

When negative five is subtracted from a number the result is 10 find the number15
5
-5
-15

Answers

Answer: second option.

Step-by-step explanation:

Let be "x" the unknown number.

According to the information provided in the exercise, 10 is the result of the subtraction of "x" and -5.

Based on this, you can write the following equation:

$x-(-5)=10$

To find the value of "x" you must remember the multiplication of signs:

$(+)(+)=+\n(-)(-)=+\n(-)(+)=-$

Then:

$x-(-5)=10\n\nx+5=10$

Finally, subtracting 5 from both sides of the equation, you get:

$x+5-(5)=10-(5)\n\nx=5$

Answer:

x - (-5) = 10

x = 5

My final answer is 5

Step-by-step explanation:

There are 3 times as many pears are oranges. If a group of children receive 5 oranges each,there will be no left over.If the same group of children receive 8 oranges each, there will be 21 pears left over. How many oranges are there?

Answers

There are 15 oranges

Solution:

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

There are 3 times as many pears are oranges

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

If a group of children receive 5 oranges each, there will be no left over

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

If the same group of children receive 8 oranges each, there will be 21 pears left over

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

Substitute eqn 1

3x = 8c + 21 ---- eqn 3

Substitute eqn 2

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

Substitute c = 3 in eqn 2

x = 5(3)

x = 15

Thus there are 15 oranges

Answer:

15 orangs

Step-by-step explanation:

There are 15 oranges

Solution:

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

There are 3 times as many pears are oranges

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

If a group of children receive 5 oranges each, there will be no left over

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

If the same group of children receive 8 oranges each, there will be 21 pears left over

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

Substitute eqn 1

3x = 8c + 21 ---- eqn 3

Substitute eqn 2

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

Substitute c = 3 in eqn 2

x = 5(3)

x = 15

Thus there are 15 oranges

A student is trying to solve the set of two equations given below:Equation A: x + z = 6
Equation B: 2x + 4z = 1

Which of the following is a possible step used in eliminating the z-term?

Multiply equation B by 4.
Multiply equation A by 2.
Multiply equation A by –4.
Multiply equation B by 2.