Which is an example of plasmas in nature? solar cells plasma balls auroras clouds

Answers

Answer 1

Answer:

The best example of natural plasma is the ionosphere of the atmosphere including solar corona and lightning including auroras cloud.

What is natural plasma?

the heated or hot matter that is so hot that the electrons are thrown away from the atoms and forms the ionized gas. Comprises over 99% of the visible universe.

Lightning strikes create plasma by doing a stricking of electricity. Mostly the Sun, and some stars, are in a plasma state. Certain regions of Earth's atmosphere contain some plasma created primarily by ultraviolet radiation from the Sun.

One reason plasma is not so common is because this needs high temperatures required to keep gas in the plasma state. At average temperatures on Earth, there just isn't enough energy for atoms to remain ionized.

However, at thousands to millions of degrees Kelvin, these energies are available, and plasmas dominate

Therefore, aurora clouds are natural plasma.

Learn more about natural plasma ,here

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Answer 2

Answer:

Answer:

aurorus

Explanation:

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A balloon has a volume of 7.00 liters at a pressure of 740 mm Hg. If the temperature remains constant, at what pressure will the volume decrease to 2.00 liters?a. 749 mm Hg
b. 52.9 mm Hg
c. 211 mm Hg
d. 2590 mm Hg

Answers

Answer:

Explanation:

P1 x V1 = P2 x V2

7.00(740) = x(2.00)

2590 mm Hg

took me a while because i dont know this, hope its right good luck

How many grams of NaCl are produced when 0.548 moles of Na react with excess Cl2 according to the reaction above?2Na + Cl2 --> 2NaCl

Answers

Answer:

$\boxed {\boxed {\sf 32.0 \ g \ NaCl}}$

Explanation:

To solve this problem, we must use stoichiometry: the calculation of reactants and products in a chemical reaction using ratios.

1. Analyze the Reaction

$2Na+Cl_2 \rightarrow 2 NaCl$

Check the coefficients, which indicate the moles required for the reaction. 2 moles of sodium (Na) and 1 mole of chlorine (Cl₂) produces 2 moles of sodium chloride (NaCl).

2. Set Up Ratios.

We are asked to find the grams of NaCl produced when 0.548 moles of Na react with excess chlorine.

We need 2 ratios: 1 for finding the moles of NaCl produced and 1 for converting to grams.

The first ratio is found using the coefficients. Since there is excess chlorine, we only need to focus on the sodium and sodium chloride. According to their coefficients, 2 moles of Na produce 2 moles of NaCl. This is the first ratio.

$\frac { 2 \ mol \ Na }{2 \ mol \ NaCl}$

The second ratio uses the molar mass. Since we are solving for the grams of NaCl, we have to find its molar mass.

First, locate these values on the Periodic Table for the individual elements.

Na: 22.989769 g/mol
Cl: 35.45 g/mol

There is 1 of each atom in 1 molecule, so we can add these values.

NaCl: 58.439769 g/mol

Use this value as the second ratio.

$\frac {58.439769 \ g \ NaCl}{1 \ mol \ NaCl}$

3. Calculate

Make 1 expression using the 2 ratios and the initial value of moles.

$0.548 \ mol \ Na * \frac { 2 \ mol \ Na }{2 \ mol \ NaCl} * \frac {58.439769 \ g \ NaCl}{1 \ mol \ NaCl}$

Flip the ratios so the correct units cancel out.

$0.548 \ mol \ Na * \frac { 2 \ mol \ NaCl }{2 \ mol \ Na} * \frac {58.439769 \ g \ NaCl}{1 \ mol \ NaCl}$

Multiply. Note that the moles of Na (units) cancel and the moles of NaCl (units). cancel.

$0.548 * \frac { 2 }{2 } * \frac {58.439769 \ g \ NaCl}{1}$

$\frac {0.548 *2* 58.439769 \ g \ NaCl}{2}$

$\frac {64.049986824 \ g \ NaCl}{2} =32.024993412 \ g\ NaCl$

The original value of moles has 3 significant figures, so our answer must have the same. For the number we found, that is the tenth place.

32.02499341232

The 2 in the hundredth place tells us to leave the 0.

$32.0 \ g \ NaCl$

0.548 moles of sodium react with excess chlorine to produce 32.0 grams of sodium chloride.

A 5.000 gram sample of lenthionine contains 0.6357 g carbon and 0.1070 g hydrogen, and the remainder is sulfur. The molar mass of lenthionine is 188.4 g/mol. Determine the chemical formula for lenthionine.

Answers

Answer: C2H4S5

Explanation:

Since the total mass is 5.000g

Mass of sulphur = 5.000-(0.6357+0.1070)

Mass of sulphur = 4.2573g

Using Empirical relation

C= 0.6357 H= 0.1070 S= 4.2573

Divide through by their molar mass to obtain the smallest ratio

C= 0.6357/12 H=0.1070/1 S=4.2573/32

C= 0.053 H= 0.1070 S= 0.133

Divide through by the smallest ratio (0.053)

C=0.053/0.053 H=0.1070/0.053 S=0.133/0.053

C=1 H=2 S=2.5

1:2:2.5 ,multiply through by 2 ,to obtain whole numbera

2:4:5

Therefore the empirical formula is C2H4S5. Thus only gives the ratio

Molecular formula is the chemical formula .

(Empirical formula) n = molecular formula

(C2H4S5)n = molar mass

[(12×2) + ( 1×4) +(32×5)]n = 188.4

188n=188.4

n= 1

Molecular formula = (C2H4S5)×1

Therefore the chemical formula of

lenthionine is C2H4S5

Why does ammonium nitrate (NH4NO3) dissolve readily in water even though the dissolution process is endothermic by 26.4 kJ/mol? Why does ammonium nitrate (NH4NO3) dissolve readily in water even though the dissolution process is endothermic by 26.4 kJ/mol? The vapor pressure of the water decreases upon addition of the solute. The osmotic properties of the system lead to this behavior. The overall enthalpy of the system decreases upon addition of the solute. The overall entropy of the system increases upon dissolution of this strong electrolyte. The overall enthalpy of the system increases upon dissolution of this strong electrolyte.

Answers

Answer: Option (c) is the correct answer.

Explanation:

Entropy is defined as the degree of randomness that is present within the particles of a substance.

As $NH_(4)NO_(3)$ is ionic in nature. Hence, when it is added to water then it will readily dissociate into ammonium ions ( $NH^}{+}_(4)$ ) and nitrate ions ( $NO^(-)_(3)$ ).

Therefore, it means that ions of ammonium nitrate will be free to move from one place to another. Hence, there will occur an increase in entropy.

Thus, we can conclude that ammonium nitrate ( $NH_(4)NO_(3)$ ) dissolve readily in water even though the dissolution process is endothermic by 26.4 kJ/mol because the overall entropy of the system increases upon dissolution of this strong electrolyte.

The balanced equation below shows the products that are formed when pentane (C5H12) is combusted.C5H12 + 802 → 10CO2 + 6H20
What is the mole ratio of oxygen to pentane?

Answers

Answer:

8 : 1

Explanation:

The balanced equation for the reaction is given below:

C5H12 + 8O2 → 5CO2 + 6H2O

From the balanced equation above,

1 mole of C5H12 reacted with 8 moles of O2.

Thus the mole ratio of O2 to C5H12 is:

8 : 1

Answer:

8:1 !!!

Explanation:

I Just take the test

Hydrochloric acid reacts with sodium hydroxide to produce sodium chloride and water. If 20.6 g of sodium hydroxide reacts with an excess of hydrochloric acid, how many grams of sodium chloride are produced? HCl + NaOH → NaCl + H2O

Answers

Answer:

30.1 g NaCl

Explanation:

Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.

20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl

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