A hot air balloon can hold up to 300 pounds of weight. The balloon's pilot weighs 140 pounds. How many 20-pound bags of sand (b) can also be carried by the hot air balloon? Select THREE options. (1) –2
(2) 0
(3) 5
(4) 8
(5) 10

Answers

Answer 1
Answer:

The possible values of 20-pound bags of sand will be;

⇒ 0, 5, 8

What is Inequality?

A relation by which we can compare two or more mathematical expression is called an inequality.

Given that;

A hot air balloon can hold up to 300 pounds of weight.

And, The balloon's pilot weighs 140 pounds.

Now,

Let number of possible values of 20-pound bags of sand = b

So, We can formulate;

⇒ 20b + 140 ≤ 300

Solve for b as;

⇒ 20b ≤ 300 - 140

⇒ 20b ≤ 160

⇒ b ≤ 8

Thus, The possible values of 20-pound bags of sand are;

⇒ 0, 5, 8

Learn more about the inequality visit:

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Answer 2
Answer:

Answer:

8

Step-by-step explanation:

You subtract 300 from 140 to get 160 because the pilot adds the weight in already. Once you get 160 divides it by 20 to get 8. Each bag weighs 20 pounds, every bag you add will decrease the total the air balloon can carry, so anything 8 and less is good. (4), (5), and (0) should be your answer.


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Use elimination to solve this system of equations. X-4y=-11 and 5x-7y=-10

Answers

x-4y=-11<=> -5x + 20y = 55
                      5x - 7y    = -10
                =>0*x + 13*y = 45 => y =45/13 => x = 4*(45/13) -11 = 180/13 -11 =>
x = 37/13;

Please someone help me i do not know the answer

Answers

Answer:

For #9, the part of the expression that represents the quotient is the division problem in parenthesis. Specifically, "(45 ÷ 9)". I believe you only need the division symbol for this, though. Correct me if I'm wrong.

As for #10, the part of the expression representing the product of two factors is 5.2 being multiplied by the variable u. This results in the the term 5.2u, with the coefficient being 5.2 and the variable being u.

What is  ³√16 simplified?


Answers

\sqrt[3]{16}= \sqrt[3]{8\cdot 2}=\sqrt[3]{8}\cdot \sqrt[3]{2}=2\sqrt[3]{2}


Using completing the square to solve for x in the equation (x-12)(x+4)=9

Answers

Answer:

x = 4 + √73

Step-by-step explanation:

The given equation is ( x-12 ) ( x + 4 ) = 9

We will solve the equation first.

( x - 12 ) ( x + 4 ) = 9

x( x+4 ) - 12 ( x + 4 ) = 9 [ Distributive property ]

x² + 4x - 12x - 48 = 9

x² - 8x - 48 = 9

x² - 8x - 48 - 9 = 0

x² - 8x - 57 = 0

[ x² - 2 (4x) + 16 ] - 57 - 16 = 0

(x - 4)² - 73 = 0

(x - 4)² = 73

( x-4 )² = √73

x = 4 + √73

x = 4 + √73 is the answer.

Hello!

You can multiply (x-12) and (x+4)

x * x = x^2
x * 4 = 4x
-12 * x = -12x
-12 * 4 = -48

Now we have

x^2 - 8x - 48 = 9

Subtract 9 from both sides

x^2 - 8x -57 = 0

Use the quadratic formula

This give use the answer of

x = 4 +√(72)

Hope this helps!

A quadrilateral ___________ has one pair of parallel sidesalways
sometimes
never
inconclusive

Answers

A quadrilateral sometimes has one pair of parallel sides. Then the correct option is B.

What is a quadrilateral?

The quadrilateral has four sides and four angles. The sum of internal angles is 360 degrees.

If the quadrilateral has one pair of parallel sides is known as a trapezoid. And if the quadrilateral has two pairs of parallel sides is known as a parallelogram.

If all the angles are congruent then the parallelogram becomes a rectangle. And if all the sides are congruent then the parallelogram becomes a rhombus. If both sides and angles become congruent in the parallelogram then is known as a square.

A quadrilateral sometimes has one pair of parallel sides. Then the correct option is B.

More about the quadrilateral link is given below.

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A  quadrilateral always has one pair of parallel sides.

Jan's scores on five quizzes were 2, 8, 8, 9, and 10. Is the mean or median the best measure of center to summarize Jan's scores?

A.median

B.mean

C.Both mean and median summarize the data equally well.

Answers

the median is truly the middle of the data set. But the mean describes the average i want you to decide so i wont get this wrong. Thus, is the mean more important than the median according to this information?