Simplify the expression 4^2+8÷2

Answers

Answer 1

Answer: the answer is 20,
16+8/2
16+4
20

Answer 2

Answer: The answer is 12
4^2 =16
16+8= 24
24/2=12

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N ∈ lNWe set A= n(n²+11)
Show that A is divisible by 3
( n is natural number )
please try to help me in this i need it tomorrow plz...

Answers

@Konrad509's answer was fantastic.

What you first need to know is this. 3 consecutive natural numbers multiplied by each other, for instance: (1*2*3) or (2*3*4) or (3*4*5) or (4*5*(2*3)) can be described using the abstract expression:

(n-1)n(n+1)

-------------

Now:

A=n(n²+11),

and:

n(n²+11)

=n(n²-1+12)

=n³-n+12n

=n(n²-1)+12n

=n(n+1)(n-1)+12n

=(n-1)n(n+1)+(4*3)n

-------------------------

So:

A=(n-1)n(n+1)+(4*3)n

Therefore, A is divisible by 3.

$n(n^2+11)=\nn(n^2-1+12)=\nn(n^2-1)+12n=\n(n-1)n(n+1)+12n$

$(n-1)n(n+1)$ is the product of 3 consecutive natural numbers, so it has be to divisible by 3.

$12n$ is also divisible by 3 because 12 is divisible by 3.

If both elements of the sum are divisible by 3 so the sum itself is divisible by 3 as well.

If the width and height of a rectangular prism are each shrunk to one seventh of the original size but the length remains the same, what is the formula to find the modified surface area?

Answers

Hey there,

Let's say 'L'=length, 'W'=width, and 'H'=height.

The surface area of a rectangular prism is

   A = (2LW) + (2WH) + (2LH) = 2 (LW + WH + LH)

If you shrink the width and height, then the new width is W/7
and the new height is H/7.

The new surface area is

   A = (2 L W/7) + (2 W/7 H/7) + (2 L H/7) .

That's    A = 2 (LW/7 + WH/49 + LH/7) .

or you could write it as   A = 2/7 (LW + WH/7 + LH)

There are many more ways to massage the formula and write it
in different ways, but I think writing it just that way is OK.

AEFGH is a rhombus. Given EG = 22 and FH = 20, what is the length of one side of the rhombus?
Please help :/

Answers

Applying the properties of a rhombus and the Pythagorean Theorem, the length of one side of the rhombus is: 14.9

Recall:

The diagonals of a rhombus bisect each other at right angles, thereby forming 4 right triangles.

Half of a diagonal and half of the other diagonal make up a right triangle.

Thus, given:

EG = 22 (diagonal)
FH = 20 (diagonal).

Find the length of one side using Pythagorean theorem as shown below:

$HG = \sqrt{((1)/(2)EG)^2 + ((1)/(2)FH)^2 } \n\n$

Substitute

$HG = \sqrt{((1)/(2) * 22)^2 + ((1)/(2) * 20)^2 } \n\nHG = √(11^2 + 10^2) \n\n\mathbf{HG = 14.9}$

Therefore, applying the properties of a rhombus and the Pythagorean Theorem, the length of one side of the rhombus is: 14.9

Learn more here:

brainly.com/question/24618146

Solve this..➕+ ➕ + ➕+ ➕=30
Fill the boxes using (1, 3, 5, 7, 9, 11, 13, 15)
U can also repeat the numbers..

Answers

These are all possible combinations:
1 , 1 , 13 , 15
1 , 3 , 11 , 15
1 , 3 , 13 , 13
1 , 5 , 9 , 15
1 , 5 , 11 , 13
1 , 7 , 7 , 15
1 , 7 , 9 , 13
1 , 7 , 11 , 11
1 , 9 , 9 , 11
3 , 3 , 9 , 15
3 , 3 , 11 , 13
3 , 5 , 7 , 15
3 , 5 , 9 , 13
3 , 5 , 11 , 11
3 , 7 , 7 , 13
3 , 7 , 9 , 11
3 , 9 , 9 , 9
5 , 5 , 5 , 15
5 , 5 , 7 , 13
5 , 5 , 9 , 11
5 , 7 , 7 , 11
5 , 7 , 9 , 9
7 , 7 , 7 , 9

There can be a lot many solutions for the above question
some of them are
9+11+5+5=30
it can also be solved as
15+5+5+5=30
also
13+7+5+5=30

What is the length of a rectangle with width 10 inches and area 45 inches^2? Use 3.14