So we want to perform a change of units for the weight of a box of cereal. We will see that it weighs 12 ounces.
We know that it weighs 0.75 pounds, and we want to know how many ounces it weighs.
And we know that:
Then we can rewrite the weight as:
W = 0.75 lb = 0.75*( 1 lb) = 0.75*(16 oz) = 12 oz
So the box of cereal weighs 12 ounces.
If you want to learn more, you can read:
Answer:
24
Step-by-step explanation:
one cup is 8 ounces times three is 24
Answer:
42 in each basket 4 leftover
Step-by-step explanation:
6 divided by 256 = 42 R4 and the remainder is how many are leftover.
Answer:
-1/4 , -1
Step-by-step explanation:
I solved it using Factorization method and Quadratic Equation .
Factorization Method
Quadratic Equation
Find the lower quartile and upper quartile of
the data set.
lower quartile: $
upper quartile: S
?
$1.39 $1.40 $1.44 $1.50 $1.60 $1.63 $1.65 $1.80
Answer:
Lower quartile: $1.42
Upper quartile: $1.64
Step-by-step explanation:
The median is the middle value when all data values are placed in order of size.
The ordered data set is:
$1.39 $1.40 $1.44 $1.50 $1.60 $1.63 $1.65 $1.80
There are 8 data values in the data set, so this is an even data set.
Therefore, the median is the mean of the middle two values:
Place "||" in the middle of the data set to signify where the median is:
$1.39 $1.40 $1.44 $1.50 ║ $1.60 $1.63 $1.65 $1.80
The lower quartile (Q₁) is the median of the data points to the left of the median. As there is an even number of data points to the left of the median, the lower quartile is the mean of the the middle two values:
The upper quartile (Q₃) is the median of the data points to the right of the median. As there is an even number of data points to the right of the median, the upper quartile is the mean of the the middle two values:
Answer:
to find the lower quartile and upper quartile of the given dataset, we need to first arrange the data in ascending order:
$1.39, 1.40, 1.44, 1.50, 1.60, 1.63, 1.65, 1.80$
The median of the dataset is given as $1.55$. Since there are an even number of data points, the median is the average of the two middle values, which in this case are $1.50$ and $1.60$.
Now, we need to find the lower quartile and upper quartile. The lower quartile is the median of the lower half of the data set, and the upper quartile is the median of the upper half of the data set.
The lower half of the dataset is $1.39, 1.40, 1.44, 1.50$. The median of this half is the average of the middle two values, which are $1.40$ and $1.44$.
Therefore, the lower quartile is $1.42$.
The upper half of the dataset is $1.60, 1.63, 1.65, 1.80$. The median of this half is the average of the middle two values, which are $1.63$ and $1.65$.
Therefore, the upper quartile is $1.64$.
Hence, the lower quartile of the dataset is $1.42$ and the upper quartile is $1.64$.
Answer:
The bottom left table
Step-by-step explanation:
the same x value cannot have different y values
A)
the Roman Empire.
B)
the Roman Republic.
Egypt's "New Kingdom."
D)
Alexander the Great's Empire.
Submit
Answer:
it b 100%
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
a) The histograms suggest that the distributions of adoptions in each region are skewed to the right.
b) The histograms look similar because they both show similar patterns of adoption distribution among different regions.
c) A better way to express the number of adoptions might be to use adoption rates or percentages relative to the population size in each region.
a) The histograms show the distribution of adoptions in each region. The horizontal axis represents the number of adoptions, and the vertical axis represents the frequency (or count) of regions with a specific number of adoptions. Each bar in the histogram represents a specific number of adoptions and its height indicates how many regions have that number of adoptions.
b) The histograms look similar because they both show the distribution of adoptions in different regions. They have a similar shape, with the majority of regions having a lower number of adoptions, and a few regions having a higher number of adoptions. This similarity suggests that the adoption patterns in different regions follow a similar trend.
c) A better way to express the number of adoptions might be to use percentages or rates. Since the population of each region is different, the raw number of adoptions alone might not provide a fair comparison. By calculating the adoption rate (number of adoptions per 1000 people, for example) or expressing the number of adoptions as a percentage of the total population in each region, we can get a clearer picture of the adoption trends relative to the population size in each region.
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The histograms indicate that higher population regions tend to have more adoptions. They are similar as adoption rates and population sizes are interlinked. A better representation might be the adoption rate per population quota, which shows comparison between regions clearer.
a) The histograms show the "distribution of adoptions" and the "population of each region." We can infer that the distribution of adoptions largely mirrors the population distribution, meaning that regions with larger populations tend to have more adoptions.
b) The histograms look similar because adoption rates and population size are related. If a region has a larger population, it likely has more families, hence more potential for adoption.
c) A better way to express the number of adoptions might be to calculate the adoption rate per population. For example, the number of adoptions per 1,000 or 10,000 population members. This way, it directly relates the number of adoptions to the size of the population, and provides a percentage or ratio rather than absolute numbers. This method can be more helpful in making comparisons between regions.
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