Removing which point from the coordinate plane would make the graph a function of x? On a coordinate plane, points are at (negative 2, negative 3), (negative 2, 1), (negative 4, 3), (0, 4), (1, 1), and (2, 3).

Answers

Answer 1

Answer:

Answer: The first or the second point (- 2, - 3) or (- 2, 1)

Step-by-step explanation:

Ok, a relation (x, y) is a function only if, for each value x in the domain, we have only one value y in the range such that:

f(x) = y.

Here we have the pairs:

(- 2, - 3), (- 2, 1), (- 4, 3), (0, 4), (1, 1), and (2, 3).

Here, for the value x = -2, we have two different values of y.

y = 1 and y = 3.

So this is not a function, then if we want that this relation becomes a function, we must remove the first or the second point.

Answer 2

Answer:

Answer:

I think B

Step-by-step explanation:

Related Questions

Use the three steps to solve the problem. The sum of 3 consecutive integer numbers is 117. Find the numbers. List your answers separated by a comma. a) 38, 39, 40 b) 39, 40, 41 c) 40, 41, 42 d) 41, 42, 43
If f'(x) = ln (x-2), then the graph of y=f(x) is decreasing if and only if a) 2b) 0c) 0d) x>1e) x>2
At the register Annie notices her grocery bill was marked with $14 for the 7 pounds of meat she purchased. What is another wayof saying this ratio?
Choose the graph of the function given below.f(x) = 2x+1
Which expression is equivalent to 10 - 810−810, minus, 8?

The width of a rectangle is 12 cm less than the length. The perimeter is 156 cm. Find the width and length.

Answers

$w-the\ width\nl-the\ length\n\nw=l-12\n\nthe\ perimeter\ of\ rectangle:P=2(w+l)\ and\ P=156cm\n\n2(w+l)=156\to\ put\ w=l-12\ to\ equation:\n\n2(l-12+l)=156\n2(2l-12)=156\ \ \ \ |divide\ both\ sides\ by\ 2\n2l-12=78\ \ \ \ \ |add\ 12\ to\ both\ sides\n2l=90\ \ \ \ \ |divide\ both\ sides\ by\ 2\nl=45\n\nw=45-12=33\n\nSolution:the\ width\ equal\ 33cm\ and\ the\ length\ equal\ 45cm.$

Multiply the decimal numbers 37.4 x 2.2 =

Answers

Basically you multiply like normal and then add in the decimal point (to figure out where it goes count how many numbers are behind the decimal (in this case 2) and then count that many places from the right into your answer and that's where it goes). So here 374 x22 =8228 but when you add in the decimal you get 82.28 :)

82.28 because once you finish multipling, you havs to movd the decimal which in this case would be two spaces to the left starting from the right

Find the range of {(3.2, –3), (7.6, 5.9), (1.4, –3), (–9.1, 8.3)}.

Answers

Answer:

range is -3, 5.9 , 8.3

Step-by-step explanation:

{(3.2, –3), (7.6, 5.9), (1.4, –3), (–9.1, 8.3)}

We are given with set of ordered pairs (x,y)

In each ordered pair, x is the domain and y is the range

for domain , take all the x values (first number) from the ordered pairs

for range, take all the y value (second number) from the ordered pairs

y values of the ordered pairs are -3, 5.9, -3, 8.3

So range is -3, 5.9 , 8.3

Answer:

{(3.2, –3)}

Step-by-step explanation:

The domain is the set of all the values of

x .The range is the set of all the values of y .

Domain: { 3.2 , 7.6 , 1.4 , − 9.1 }

Range: { − 3 , 5.9 , 8.3 }

What is the value of A for the exponential function in the graph represented in the form of f(x) = a(bx)?

Answers

Answer:

a = 3

Step-by-step explanation:

f(x) = a(bˣ)

At x = 0

f(0) = a(b⁰)

f(0) = a(1)

f(0) = a

From the graph

f(0) = 3

Therefor

a = 3

I am a solid figure with faces that are polygons.

Answers

Hey There!

A solid figure with polygon faces is called the Polyhedron.

Have A Brainly Day :)

A polyhedron

Let God bless your night !

Choose the abbreviation of the postulate or theorem that supports the conclusion that the triangles are congruent.Given:
∠C, ∠F are rt. ∠'s; AC = DF; ∠B = ∠E

HL
LL
HA
LA

Answers

∠C and ∠F are right angles. So, the triangles are right triangles.

AC = DF are the short legs of both triangles.

∠B = ∠E.

In this scenario, the postulate is ASA (Angle-Side-Angle)

The remaining sides that must be noted to prove that the triangles are congruent are the long legs and hypotenuse.

CB = FE can be LL for congruence where tt states that if the legs of one right triangle are congruent to the legs of another right triangle, then the triangles are congruent.

Nameof postulate or theorem that supports the conclusion that the triangles are congruent is Angle-side-Angle (ASA).

Given information:

$\angle C,\; \angle F$ are right triangle, $AC=DF;\angle B=\angle E$