Pleaseeee help me with thissss pleaseeee
pleaseeee help me with thissss pleaseeee - 1

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

56. 6x = 132

      x = 22

57. 2/3 = -8x

     -24x = 2

        x = -2/24= -1/12

58. 5/11x = 55

      5x = 605

       x = 121

59. 4/5 = 10/16x

       4/5 = 5/8x

        23 = 25x

        23/25

60. 3 2/3x = 2/9

      11/9x = 2/9

      11x = 2

      x = 2/11

61. 4 4/5x = 1 1/5

      24/5x = 6/5

      24x = 6

     x = 6/24 = 1/4


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PLSSS ANSWER I DONT HAVE LOTS OF TIMEEE!!?!?!?!?!?!??!??!??! Three families took a vacation to Phoenix. The Abbott Family spent $840 on four nights at their hotel and three airline tickets. The Baker Family spent $1,130 on nine nights at their hotel and two airline tickets. The Carson Family spent $2,080 on six nights at their hotel and five airline tickets. Two of the families paid the same price per night at their hotel and per airline ticket.Which two families would have had to pay the same price per night at their hotel and per airline ticket to have the largest possible nightly hotel cost?
A.
the Abbott and Baker Families

B.
the Abbott and Carson Families

C.
the Carson and Baker Families

D.
all three families would have to pay the same price

Answers

Answer:

c

Step-by-step explanation:

both of the familys have higher cost and have to stay longer

Final answer:

After solving systems of equations for each pair of families, the Abbott and Carson Families are the ones that fit the conditions allowing the largest possible nightly hotel cost.

Explanation:

Let's examine the vacation expenses for each family to determine which two families could have paid the same price per night at their hotel and per airline ticket for the largest possible nightly hotel cost. We must establish a system of equations to represent the total vacation expenses in terms of hotel cost per night (H) and airline ticket cost (A).

For the Abbott Family:
4H + 3A = $840

For the Baker Family:
9H + 2A = $1,130

For the Carson Family:
6H + 5A = $2,080

To determine which two families could have the same hotel and ticket costs, we should look for the two equations that can be true simultaneously for the highest values of H. For ease of calculation, we can eliminate one family at a time and solve the remaining pair of equations for H and A.

By trying different combinations, we can find that the Abbott and Carson Families fit the conditions allowing the largest possible nightly hotel cost. Here's the reasoning:

  • If the Abbott and Baker families paid the same rates, then solving the equations yields illogical negative values for the costs.
  • If the Carson and Baker families paid the same rates, the solution yields a lower hotel rate compared to the Abbott and Carson combination.
  • Using the Abbott and Carson families' equations, and solving for H and A yields feasible positive values, with the highest cost per night for the hotel.

Hence, option B, the Abbott and Carson Families, is the right choice for the largest possible nightly hotel cost.

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Please help me solve this problem

Answers

Answer:A

Step-by-step explanation:

The dot means less than or equal to 2

Open dot means greater than 2

A comet travels at an average speed of 233,000 km/h. It takes 7 days for the comet to reach Earth.
Find the distance, in km, the comet travelled.

Answers

Answer:

39,144,000 km

Step-by-step explanation:

Hi there!

Distance traveled = time * speed

Given speed: 233000 km/h

Given time: 7 days

It's important to note that our speed is given in per hours and out time is given in days. So in order to find how far the comet has traveled we must convert days to hours.

There are 24 hours in 1 day.

So to convert days to hours simply multiply amount of days by 24

24 * 7 = 168

So the comet has traveled for 168 hours

Now we can find distance traveled

Once again distance traveled = time * speed

Given speed is 233000 km/h

Given time is 168 hours

Distance = 168 * 233000 = 39,144,000

So the comet has traveled for a total distance of 39,144,000 km

Factor the polynomial below X cubed +12 X squared +36X

Answers

I’m sorry but I have no idea

Xpress 8.54545454545... as a rational number, in the form pq where p and q are positive integers with no common factors.

Answers

To express the repeating decimal 8.54545454545... as a rational number, we can use the concept of infinite geometric series. The rational number equivalent is 282/33.

To express the repeating decimal 8.54545454545… as a rational number, we can use the concept of infinite geometric series. Let x = 8.54545454545…, then multiplying x by 100 gives 100x = 854.54545454545…. Next, subtracting the original x equation from the 100x equation eliminates the repeating decimals, giving 99x = 846. Dividing both sides by 99 results in x = 846/99. Simplifying the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 3, gives the final answer: x = 282/33.

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If you mean p/q, then this is how you do it:

x = (846)/(99) = (94)/(11)

Therefore your final answer is 94/11, where p is 94 and q is 11.

Paul owns a mobile wood-fired pizza oven operation. A couple of his clients complained about his dough at a recent catering, so he changed his dough to a newer product. Using the old dough, there were 6 complaints out of 385 pizzas. With the new dough, there were 16 complaints out of 340 pizzas. Let p 1 be the proportion of customer complaints with the old dough and p 2 be the proportion of customer complaints with the new dough. State the competing hypotheses to determine if the proportion of customer complaints using the old dough is less than the proportion of customer complaints using the new dough g

Answers

Answer:

z=\frac{0.0156-0.0471}{\sqrt{0.0303(1-0.0303)((1)/(385)+(1)/(340))}}=-2.469    

Now we can calculate the p value with this probability:

p_v =P(Z<-2.469)= 0.0068    

Since the p value is a very low value and using any significance level 5% or 10% we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of customer complaints using the old dough is less than the proportion of customer complaints using the new dough.

Step-by-step explanation:

Information provided

X_(1)=6 represent the complaints with the old dough

X_(2)=16 represent the complaints with the new dough

n_(1)=385 sample 1 selected  

n_(2)=340 sample 2 selected  

p_(1)=(6)/(385)=0.0156 represent the proportion of complaints with the old dough

p_(2)=(16)/(340)=0.0471 represent the proportion of complaints with the new dough

\hat p represent the pooled estimate of p

z would represent the statistic

p_v represent the value

Hypothesis to test

We want to verify if the proportion of customer complaints using the old dough is less than the proportion of customer complaints using the new dough, the system of hypothesis would be:    

Null hypothesis:p_(1) \geq p_(2)    

Alternative hypothesis:p_(1) < p_(2)    

The statitsic is given by:

z=\frac{p_(1)-p_(2)}{\sqrt{\hat p (1-\hat p)((1)/(n_(1))+(1)/(n_(2)))}}   (1)  

Where \hat p=(X_(1)+X_(2))/(n_(1)+n_(2))=(6+16)/(385+340)=0.0303  

Replacing the info provided we got:

z=\frac{0.0156-0.0471}{\sqrt{0.0303(1-0.0303)((1)/(385)+(1)/(340))}}=-2.469    

Now we can calculate the p value with this probability:

p_v =P(Z<-2.469)= 0.0068    

Since the p value is a very low value and using any significance level 5% or 10% we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of customer complaints using the old dough is less than the proportion of customer complaints using the new dough.