How do you do this question?
Answers
Step-by-step explanation:
∫ dt / (cos²(t) ⁹√(1 + tan(t)))
If u = 1 + tan(t), then du = sec²(t) dt.
∫ du / ⁹√u
∫ u^(-1/9) du
9/8 u^(8/9) + C
9/8 (1 + tan(t))^(8/9) + C
Related Questions
Help please points and brainlest!!
What’s the least common multiple of 30 50 and 200
The State Police are trying to crack down on speeding on a particular portion of the Massachusetts Turnpike. To aid in this pursuit, they have purchased a new radar gun that promises greater consistency and reliability. Specifically, the gun advertises ± one-mile-per-hour accuracy 75% of the time; that is, there is a 0.75 probability that the gun will detect a speeder, if the driver is actually speeding. Assume there is a 1% chance that the gun erroneously detects a speeder even when the driver is below the speed limit. Suppose that 72% of the drivers drive below the speed limit on this stretch of the Massachusetts Turnpike. a. What is the probability that the gun detects speeding and the driver was speeding? b. What is the probability that the gun detects speeding and the driver was not speeding? c. Suppose the police stop a driver because the gun detects speeding. What is the probability that the driver was actually driving below the speed limit?
What expression represents 16 more than 5 times a number, n?
Answers
4 + 8 ln(x) = 2
8 ln(x) =
by exponentiating both sides.
x =
Answers
Answers
the answer is "The student can have only one blood type, so the actual events are mutually exclusive. "
The probabilities are not mutually exclusive. Based on the group
P(Type O) = 9/20 = 45% or 0.45
P(Type A) = 2/5 = 40% or 0.40
P(Other) = 3/20 = 15% or 0.15
I hope my answer helped you. Feel free to ask more questions. Have a nice day!
A group of students is donating blood during a blood drive. a student has 9/20 probability of having type 'o' blood and a 2/5 probability of having type 'A'.what is the probability that a student has type 'o' or type 'a' blood and why?
The student can have only one blood type, so the actual events are mutually exclusive.
28+3(5d-3)
Answers
Answer:
15d+19
Step-by-step explanation:
distribute 3(5d-3) first
= 15d-9
the expression is now 28+15d-9
combine 28 and -9
=19
bam u now have 15d+19
Answers
When y = -6 and z = 5, the value of the expression y + z + 2 is 1.
To calculate the expression y + z + 2 when y = -6 and z = 5, you simply substitute these values into the expression and perform the arithmetic operations:
y + z + 2 = (-6) + (5) + 2
Now, perform the addition:
(-6) + (5) + 2 = -1 + 2 = 1
So, when y = -6 and z = 5, the value of the expression y + z + 2 is 1.
for such more question on expression
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Answer:
1
Step-by-step explanation:
y + z + 2
first you have to replace the variables with the numbers
This is your equation now.
-6 + 5 + 2
Now you just have to solve it.
-6 + 5 = -1+ 2 = 1
or
7 - 6 = 1
Answers
Step-by-step explanation:
We know that this particularly line can be named as :
- JK ←→
- LM ←→
This give us the following information :
- The line passes through the points J and K
- The line passes through the points L and M
One statement we can make is :
The points J , K , L and M are aligned. So the line passes through the points J , K , L and M.
We also know that given a line there are infinite planes that contain the line.
Given that the points J , K , L and M belong to the same line, we can state that :
There are infinite planes that contain the points J , K , L and M.