Answer:
38,640g
Explanation:
Since the density is in g/mL, we have to convert 2.000 liters to mil-liters to be able to successfully use the formula of M=V*D. Convert liters to mil-liters and you should have 2000mL in which you can plug into the equation of M= 2000mL*19.32g/mL, mL cancels, and you're left with 38,640g (here the significant figures are already in check).
The mass of liquid gold in a 2-liter soda bottle would be 38640 grams. This is calculated by multiplying the volume of the bottle (2 liters, or 2000 mL) by the density of liquid gold (19.32 g/mL).
Density characterizes how much mass is packed into a given volume. In this case, we know that the density of liquid gold is 19.32 g/mL. Since 1 Liter equals 1000 mL, Our soda bottle has a volume of 2.000 liters or 2000 mL. To determine the mass of the liquid gold in this volume, we perform a simple multiplication: density * volume = 19.32 g/mL * 2000 mL = 38640 grams.
So, if the 2-liter bottle is completely filled with liquid gold, the mass of the gold would be 38640 grams.
#SPJ2
Answer:
T₂ = 379.4 K
Explanation:
Given data:
Initial volume = 1.56 L
Initial temperature = 20°C (20+273 = 293 K)
Final volume = 2.02 L
Final temperature = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁ /V₁
T₂ = 2.02 L × 293 K / 1.56 L
T₂ = 591.86 L.K / 1.56 L
T₂ = 379.4 K
b. suspension.
c. solvent.
d. solute.
Answer:
suspension
Explanation:
the atomic theory
elements
the periodic table
the frequency in Hertz
the Energy in Joules
492 mm Hg
740 mm Hg
805 mm Hg
Answer:
805 mmHg is the pressure when the container is compressed
Explanation:
Initial Volume of the gas, V = 55.0 L
Initial Moles of the gas, n = 2.4 mol
Initial Pressure of the gas ,P=760 mmHg
initial temperature of the gas, T = 280 K
Using an Ideal gas equation:
...(1)
Final Volume of the gas, V '= 43.0 L
Final Moles of the gas, n' = 1.8 mol
Final Pressure of the gas = p'
Final temperature of the gas, T' =36 °C = 309 K
Using an Ideal gas equation:
..(2)
(1)=(2)
P' = 805 mmHg
805 mmHg is the pressure when the container is compressed.
A. AlCl3 + H2 Al + HCl
B. Al + HCl AlCl3 + H2
C. Al HCl + AlCl3 + H2
D. Al + HCl AlCl3 + H2O
B. Al +HCI AICI3 +H2. I hope this helps