Initially, Greg has a total of 60 DVDs and CDs in his collection. He then sold 1/8 of his CDs and 1/2 of his DVDs. If the number of DVDs he sold is twice the number of CDs he sold, how many DVDs did he sell?

Answers

Answer 1

Answer:

Greg has 40 CD's and 20 DVD's. He sold 10 DVDs and 1/8 of his CD(40/8 = 5).

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

Initially, Greg has a total of 60 DVDs and CDs in his collection.

He then sold 1/8 of his CDs and 1/2 of his DVDs.

Let the number of CD is c and DVD is d

c + d = 60

2(c/8) = d/2

d = 60 - c

4(2c/8) = 4(60-c)/2

c = 120 - 2c

c = 40

d = 60-40 = 20

Thus, Greg has 40 CD's and 20 DVD's. He sold 10 DVDs and 1/8 of his CD(40/8 = 5).

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Answer 2

Answer:

Answer:

10 DVD's were sold.

Step-by-step explanation:

c = number of CD's

d = number of DVD's

so we know:

c + d = 60

2*c/8 = d/2

this can be solved:

d = 60 - c

2c / 8 = (60-c)/2

4*(2c/8) = 4*(60-c)/2 [multiply by 4]

c = 120 - 2c

3c = 120

c = 40

d = 60-40 = 20

So Greg had 40 CD's and 20 DVD's. He sold half of his DVD's, i.e., 20/2=10 and 1/8 of his CD, i.e., 40/8 = 5

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Consider f(x)=2|x|What is the rate of change over the interval 0≤x≤4?

How is the rate of change over this interval related to the form of the function?

Answers

Answer:

Please check the explanation.

Step-by-step explanation:

As we know that the average rate of change of f(x) in the closed

interval [a, b] is

$(f\left(b\right)-f\left(a\right))/(b-a)$

Given the interval [a, b] = [0, 4]

$f(x)=2|x|$

$f(b)=f(2)=2\cdot \:4$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$= 8$

$f(x)=2|x|$

$f(a)=f(0)=2\cdot \:0$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$= 0$

so the average rate of change :

$(f\left(b\right)-f\left(a\right))/(b-a)=(8-0)/(4-0)$

$=(8)/(4)$

$= 2$

We know that a rate of change basically indicates how an output quantity changes relative to the change in the input quantity. Here, it is clear the value of y increase with the increase of input.

How to you get the mean in math

Answers

The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers.

Find the difference in altitude between Mt. Rainier, Washington, 4392 mabove sea level, and Death Valley, California, 86 m below sea level.

Answers

Answer:

4478 m

Step-by-step explanation:

Answer:

4478 m.

Step-by-step explanation:

That is 4392 - (-86)

= 4392 + 86

= 4478 m.

Question: Michelle is making goodie bags for Christmas filled with chocolate and candy. Chocolates cost $2.50 per lb and candy cost $3.00 per lb. Michelle spent a total of $40 on 20 lbs of candy. How much of each kind of candy did she purchase ?

Answers

Michelle purchased 5 lbs of chocolates and 5 lbs of candy.

Let assume Michelle purchased x lbs of chocolates and y lbs of candy.

According to the given information,

Michelle spent a total of $40 on 20 lbs of candy.

So, the equation can be set up as:

Equation 1: 2.50x + 3.00y = 40

As, the totalweight of candy is 20 lbs, so we have:

Equation 2: x + y = 15

From equation 2: x = 15 - y

Substitute the value of x= 15 - y into Equation 2 as

2.5(15-y) + 3y = 40

37.5 - 2.5y + 3y= 40

0.5y = 2.5

y= 5

Substituting y= 5 into the second equation

x + 5 = 10

x = 10 -5

x = 5

Thus, 5 lbs of chocolates and 5 lbs of candy were bought.

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The question attached have incorrect values, the correct question is

Michelle is making goodie bags for Christmas filled with chocolate and candy. Chocolates cost $2.50 per lb and candy cost $3.00 per lb. Michelle spent a total of $40 on 15 lbs of candy. How much of each kind of candy did she purchase ?

the answer will be 80

All of the following fractions are equal 1/2 to except:A.5/10
B.20/40
C.4/6
D.9/18