A nurse mixes 50 cc of a 60% saline solution with a 10% saline solution to produce a 20% saline solution. How much of the 10% solution should he use?

Answer:

The nurse should use 200cc of the 10% saline solution in order to produce a 20% saline solution.

Step-by-step explanation:

to the given mix we add a quantity of a lower mix to generate another.

50cc at 60% + Xcc at 10% = (50 + X)cc at 20%

50 x 60% + X x 10% = (50 + X) x 20%

30 + 0.1X = 10 + 0.2X

30 - 10 = 0.2X - 0.1X

20 = 0.1X

20/0.1 = X

X = 200

Final answer:

To produce a 20% saline solution, the nurse should use 200 cc of the 10% saline solution.

Explanation:

To find out how much of the 10% saline solution the nurse should use, we can set up an equation using the idea that the amount of saline in the mixture is equal to the sum of the amounts of saline in each solution.

Let's say the nurse uses x cc of the 10% saline solution. The amount of saline in the 60% saline solution will be 0.6 * 50 cc = 30 cc. The amount of saline in the 10% saline solution will be 0.1 * x cc = 0.1x cc.

Since the resulting solution is 20% saline, the total amount of saline in the mixture will be 0.2 * (50 + x) cc. Setting up the equation, we have 30 + 0.1x = 0.2 * (50 + x).

Simplifying the equation, we get 30 + 0.1x = 10 + 0.2x. Solving for x, we find that x = 200 cc.

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