One question is all I need help on.
One question is all I need help on. - 1

Answers

Answer 1
Answer: Hello,

y=x²+2x
y=3x+20

==>x²+2x=3x+20
==>x²+2x-3x-20=0
==>x²-x-20=0
==>x²-2*1/2*x+1/4-20-1/4=0
==>(x-1/2)²-81/4=0
==>(x-1/2-9/2)(x-1/2+9/2)=0
==>(x-5)(x+4)=0
==>(x=5 and y= 35 ) or (x=-4 and y=-8)



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A text font fits 12 characters per inch. Using the same font, how many characters can be expected per yard of text?

Answers

Since there are 36 inches in a yard you multiply 12 and 36. That gives you 432 characters per yard.

Answer:

432 characters

Step-by-step explanation:

First we can convert 12 characters per inch in to characters per feet. Knowing that there are 12 inches per foot we know we have to multiply the 12 characters per inch by 12, giving us 144 characters per foot. Now we have to convert characters per foot to characters per yard. Knowing there are 3 feet per yard we know we have to multiply 144 characters per foot by 3, giving us a final answer of 432 characters per yard of text.

Which of the expressions below can be factored using the difference of squares method?A. 100x2 - 55y2
B. 100x2 + 49y2
C. 100x2 - 49y2
D. 100x2 + 55y2

Answers

The expression that can be factored using the difference of squares method:
C) 100x^(2)-49y^(2)
Factorization:
100x^(2)-49y^(2) = (10x+7y)*(10x-7y)

0.06 or 0.06666666666 As a fraction

Answers

0.06 = 6/100
When simplified, that's 3/50 .

0.06666666666 = 6,666,666,666/10,000,000,000
When simplified, that's 3,333,333,333/5,000,000,000 .

if a right circular cone has a volume of 15 cubic ft and a radius of 3 ft, what is the height of the cone?

Answers

volume of cone=1/3 times height times pir^2
v=15
r=3
15=1/3 hpi3^2
15=1/3hpi9
15=9/3hpi
15=3hpi
divide 3
5=hpi
h=5/pi
pi=aprox 3.14
5/3.14=1.59

1.59 ft

Which equation correctly describes the relationship between the measures of the angle and arcs formed by the intersecting secant and tangent?m∠1=1/2(mJK−mKL)
m∠1=1/2(mJK+mKL)
m∠1=1/2mJK
m∠1=mJK−mKL

Answers

Angle m∠1 if formed by a tangent and  secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant 
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)

Answer: m∠1=1/2(mJK-KL)

Answer:

just took test, confirming this other answer is right, good luck y'all

Step-by-step explanation:

Find the center (h,k) and radius of the circle with the given equation.
x^2+y^2-18x-2y+82=64

Answers

x^2+y^2-18x-2y+82=64 = (x-9)^2 + (y-1)^2 = 64 = 8^2

Center (9 , 1 )  radius = 8
x² + y² - 18x - 2y + 82 = 64
                             -82   -82
        x² + y² - 18x - 2y = -28