A mixture can be separated into pure substances with the utilization of several techniques of physical methods like simple distillation, centrifugation, sedimentation, etc.
Simple distillation may be defined as a type of separation technique that involves the separation of solvent from a solution. This technique is utilized for purifying the liquids that comprise either nonvolatile impurities such as sand, salt, and other very small amounts of particles.
Apart from simple distillation, evaporation is also used to eliminate water or any liquid substance from a mixture. It makes the solution or mixture dry with the absolute absence of water.
The Centrifugation technique is used to separate the particles on the basis of their size, shape, density, viscosity, and rotor speed.
Therefore, with the utilization of separation techniques, one can easily separate a mixture into pure substances.
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Answer:
mixture can be separated into pure substances by simple distillation
arteries
veins
capillaries
lung
А consumer price
B. production cost
C. quantity supply
D. consumer income
Please select the best answer from the choices provided
OA
OB
С
&
D
Answer:
d)consumer income
Explanation:
Answer:
D. consumer income
Explanation:
Edge 2020
Transverse waves are bigger than longitudinal waves
A transverse wave has crests and troughs and a longitudinal has compressions and rarefactions.
Transverse waves are sound waves and longitudinal waves are light waves.
Answer:
A transverse wave has crests and troughs and a longitudinal has compressions and rarefactions.
Answer:
1.74845
Explanation:
We have the following reaction:
I2 + H2 => 2 HI
Now, the constant Kc, has the following formula:
Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b
In this case I2 is A, H2 is B and C is HI
We know that the values are:
H2 = 1 × 10 ^ -3 at 448 ° C
I2 = 2 × 10 ^ -3 at 448 ° C
HI = 1.87 × 10 ^ -3 at 448 ° C
Replacing:
Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}
Kc = 1.87 ^ 2/2 * 1
Kc = 1.74845
Which means that at 448 ° C, Kc is equal to 1.74845
Answer:
Explanation:
[H2] = 10^-3
[I2] = 2*10^-3
[HI] = 0
in equilbiirum
[H2] = 10^-3 - x
[I2] = 2*10^-3 -x
[HI] = 0 + 2x
and we know
[HI] = 0 + 2x = 1.87*10^-3
x = ( 1.87*10^-3)/2 = 0.000935
then
[H2] = 10^-3 - 0.000935 = 0.000065
[I2] = 2*10^-3 -0.000935 = 0.001065
H₂ + I ⇄ 2 HI
Initially 1 × 10⁻³ 2 × 10⁻³
Change -9.35 × 10⁻⁴ -9.35 × 10⁻⁴ +1.87 × 10⁻³
At equil 6.5 × 10⁻⁵ 1.06 5 × 10⁻³ 1.87 × 10⁻³
HI increase by 1.87 × 10⁻³M