Answer: D. NaCH3COO
Explanation:
Let's go through each of these salts and think about the reactions behind them. Keep in mind that the salt with the highest pH is the most basic.
(The underlined atoms can match the chemical formula for the salt. By matching the atoms, we can reason which bases and which acids reacted to produce a given salt.)
A. K2SO4
B. Cu2SO4
C. NH4Cl
D. NaCH3COO
Sodium acetate (NaCH3COO) has the highest pH among the given salts because it is derived from a strong base and a weak acid, resulting in a basic solution upon dissolution in water.
The question asks which salt among K2SO4, CuSO4, NH4Cl, and NaCH3COO has the highest pH. To determine this, we consider the acidic or basic nature of the ions in each compound.
Sodium acetate (NaCH3COO) is formed from sodium hydroxide (NaOH), a strong base, and acetic acid (CH3COOH), a weak acid. When this salt dissolves in water, it produces Na+ ions and CH3COO- ions. The acetate ion can react with water to produce a small amount of OH- (hydroxide ions), causing the solution to be basic.
Ammonium chloride (NH4Cl) is derived from the weak base ammonia (NH3) and hydrochloric acid (HCl), a strong acid. This salt in solution will lower the pH due to the production of H+ ions from NH4+.
Potassium sulfate (K2SO4) and Copper(II) sulfate (CuSO4) are salts of sulfuric acid (H2SO4), a strong acid, and strong bases (KOH and Cu(OH)2 respectively). Since both strong acids and strong bases completely dissociate, the resulting salts typically do not affect the pH significantly.
Of these, NaCH3COO will have the highest pH because it creates a basic solution when dissolved in water.
#SPJ3
(2) 100 K and 10 atm
(3) 500 K and 0.1 atm
(4) 500 K and 10 atm
Answer : The correct option is (3) 500 K and 0.1 atm.
Explanation :
A real gas behaves ideally at high temperature and low pressure.
The ideal gas equation is,
where,
P = pressure of gas
V = Volume of gas
R = Gas constant
T = temperature of gas
n = number of moles of gas
The ideal gas works properly when the inter-molecular interactions between the gas molecules and volume of gas molecule will be negligible. This is possible when pressure is low and temperature is high.
Therefore, the correct option is (3) 500 K and 0.1 atm.
Answer:
The correct answer is (3).
Explanation:
A real gas can behave ideally at high temperatures and low pressures. The ideal gas is correctly characterized when the intermolecular interactions between the gas molecules and the volume of the gas molecule are negligible. This is only possible when system conditions are at low pressures and high temperatures.
Have a nice day!
(2) 2.0 L of Kr (4) 1.5 L of Ar
Answer: (1) 1.0 L of Ne
Explanation: According to Avogadro's law, 1 mole of every gas occupy 22.4 Liters at STP and contains avogadro's number of particles.
Avogadro's Law: This law states that volume is directly proportional to the number of moles of the gas at constant pressure and temperature.
(At constant temperature and pressure)
Thus equal volumes contain equal number of atoms.
Hence, 1.0 liter of helium contains the same total number of atoms as
1.0 L of Ne at STP.
All matter is composed of very small particles called atoms.
All atoms of a given element are identical.
Atoms cannot be created, destroyed, or subdivided.
Atoms combine with or separate from other atoms.
Atoms combine with each other.
a. exothermic
b. endothermic
c. a chemical change
d. not possible
Answer:
A
Explanation:
B. the light-independent reactions
C. the dark reactions
D. the reactions in the mitochondria
B. the light-independent reaction is the correct answer in Edgen
Answer: The volume that gas occupy will be 820.04mL.
Explanation:
To calculate the volume of the gas at different temperature, we will use the equation given by Charles' Law.
This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
or,
where,
are the initial volume and initial temperature of the gas.
are the final volume and final temperature of the gas.
We are given:
Putting values in above equation:
Hence, the volume that gas occupy will be 820.04mL.