Given the following functions, find g(f(x)). f(x) = 2x + 1 g(x) = x2 + 6​
Given the following functions, find g(f(x)). f(x) = 2x + - 1

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

g(x) = x^2 + 6

f(x^2 + 6) = 2(x^2 + 6) + 1 = 2x^2 + 12 + 1 = 2x^2 + 13


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What is 14,000,000 in scientific notation?

Answers

Your final answer is 1.4 × 10 to the power of 7.

You have a balance of $15,300 on your credit card with an annual interest rate of 185(1.5% interest rate per month) You pay $200 this month. Did your balance go up or down?

Answers

Down

Normally, payment is first applied to interest before it is applied to the principal. Since your payment is larger than the interest, your remaining balance will go to the principal. As a result, your balance will go down.

Write 4270000 in scientific notation​

Answers

4.27x10*6
i cant get it to come up properly but its to the power of 6

The ratio of the diameters of two circles is 3:5. The circumference of the larger circle is approximately 113.1 m. What is the approximate circumference of the smaller circle?7.5 m

22.6 m

67.9 m

188.5 m

Answers

Given:
diameter of two circles  3:5
small circle : 3
large circle : 5

circumference of two circles x : 113.1
small circle : ? 
large circle : 113.1 m

3:5 = x :113.1
3*113.1 = 5*x
339.3 = 5x
339.3 / 5 = x
67.86 = x

The approximate circumference of the smaller circle is 67.9 m.

Answer: C

67.9 m

Step-by-step explanation:

For the function y = -2+5sin(pi/12(x-2)), what is the maximum value?

Answers

To get the function y = -2+5sin(pi/12(x-2)), the maximum value can be determined by differentiating the function and equating it to zero. The value of x will give the maximum value of the function.
dy/dx = 5 cos (pi/12 (x-2)) (pi/12)
dy/dx = 5 pi/12 cos(pi/12 (x-2))

Equate to zero
:
5 pi/12 cos(pi/12 (x-2)) =0
pi/12 (x-2) = 3pi/2
x = 8

Substituting,
y= -2 + 5sin( pi/12 (8-2)
y = -1.86

Answer:

i got 3

Step-by-step explanation:

Given the position function, s of t equals t cubed divided by 3 minus 12 times t squared divided by 2 plus 36 times t , between t = 0 and t = 15, where s is given in feet and t is measured in seconds, find the interval in seconds where the particle is moving to the right. (5 points)0 < t < 6


5 < t < 15


t > 15


The particle always moves to the right.

Answers

Answer:

Option D is correct.

as the particle always moves to the right

Step-by-step explanation:

Given the function:  s(t) = (t^3)/(3) - (12t^2)/(2) + 36t , 0<t<15;

where

s(t) represent the distance in feet.

t represents the time in second.

Since, when the particle is moving to the right,

⇒ s(t) is increasing.

so, v(t) =(ds)/(dt) > 0

Find the derivative of s(t) with respect to t;

Use derivative formula:

(dx^n)/(dx) = nx^(n-1)

(ds)/(dt) = (3t^2)/(3)-(24t)/(2)+36

Simplify:

(ds)/(dt) = t^2-12t+36

As (ds)/(dt) > 0

t^2-12t+36 > 0

(t-6)^2 >0               [(a-b)^2 = a^2-2ab+b^2 ]

⇒ this is always true because square of any number is always positive

Therefore, it means that the particle always moves to the right.