≈ 0.31 m/s
v = d/t
= 2m/6.5s
= 0.3079 m/s
≈ 0.31 m/s
Answer:
0.305556 m / s
Explanation:
Speed = distance / time
2 metres = 0.002 km
6.5 sec = 0.00180556 hrs
Therefore,
Speed = 0.002 / 0.00180556
= 1.1 km / hr
= 0.305556 m / s
To find the oxygen saturation level of the lake, divide the amount of dissolved oxygen in the lake's water per liter (7.4 mg/L) by the water's dissolved oxygen capacity per liter (9.4 mg/L) to get the proportion. Multiply this by 100 to convert it into a percentage (78.72%), which rounds to 79% saturation.
To calculate the oxygen saturation of the lake, we divide the amount of dissolved oxygen the lake water currently has per liter by the dissolved oxygen capacity per liter of the water, and then we convert that number to a percentage.
Here are the steps to solve this problem:
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What is the formula of the missing product?
(1) CH3OH (3) H2O
(2) HCOOH (4) H2O2
Answer : The correct option is, (4)
Explanation :
Combustion reaction : It is a reaction in which a hydrocarbon react with the oxygen gas to produces carbon dioxide as water as a products.
The given incomplete equation are :
In this equation, we see that a hydrocarbon and oxygen gas are present on reactant side and carbon dioxide are present on product side but water molecules are missing on the product side. So, we are adding water on missing side.
The given complete equation will be :
Therefore, the formula missing on product is,
The experiment shows that the atoms are mostly empty spaces with most of the mass concentrated at the center, which is the nucleus of the atom.
Rutherford's model also called Rutherfords' atomicmodel was a model describing the nuclear atom or the planetary model of the atom. It gave a description of the structure of atoms.
It was proposed the year 1911 by the New Zealand-born physicist named ErnestRutherford. This model was used to describe the atom. It described the atom as tiny and dense which has a positively charged core called the nucleus.
In the nucleus of the atom, almost all the mass is the atom is concentrated. Around the nucleus, there are the light, negative particles which are called electrons. These circulate around the nucleus at some distance like planets revolve around the Sun.
Therefore, the experiment shows that the atoms are mostly empty spaces with most of the mass concentrated at the center, which is the nucleus of the atom.
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(2) gamma radiation, alpha particle, beta particle
(3) positron, alpha particle, neutron
(4) neutron, positron, alpha particle
Answer: Option (4) is the correct answer.
Explanation:
An alpha particle is basically a helium nucleus and it contains 2 protons and 2 neutrons. Symbol of an alpha particle is or .
This means that an alpha particle carries a +2 charge.
A positron is a small particle which contains a +1 charge. And, a positron is represent by the symbol .
A neutron is a sub-atomic particle present inside the nucleus of an atom. Charge on a neutron is 0.
A gamma particle is basically a photon of electromagnetic radiation with a short wavelength.
Symbol of a gamma particle is . Hence, charge on a gamma particle is also 0.
Therefore, we can conclude that group of nuclear emissions from neutron, positron, alpha particle is listed in order of increasing charge.
The group of nuclear emissions is listed in order of increasing charge is neutron, positron and alpha particle and the correct option is option 4.
Nuclear emissions refer to the particles and radiation that are emitted from the nucleus of an atom during a nuclear reaction or radioactive decay. These emissions include alpha particles, beta particles, gamma radiation, positrons, and neutrons.
Thus, the ideal selection is option 4.
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Answer: A = -c + r
Explanation:
Answer:
a = r-c. its that simple I guess
Answer:
The atom's energy will decrease by 8.99 x 10⁻²⁶ J.
Explanation:
The atom's energy will go down by an amount equal to the energy of the photon that it emits.
The energy E of a photon is inversely proportional to its wavelength according to the following equation, where h is Planck's constant and c is the speed of light:
E = (hc)/λ
We substitute the values into the equation to solve for the energy:
E = (hc)/λ = (6.626 x 10⁻³⁴ J·s)(2.998 x 10⁸ m·s⁻¹) / 2.21 m
E = 8.99 x 10 ⁻²⁶ J
Thus, the atom's energy will decrease by 8.99 x 10⁻²⁶ J.