The safety risks are the same for technicians who work on hybrid electric vehicles (HEVs) or EVs as those who work on conventional gasoline vehicles: False.
Safety risks can be defined as an assessment of the risks and occupational hazards associated with the use, operation or maintenance of an equipment or automobile vehicle that is capable of leading to the;
Hybrid electric vehicles (HEVs) or EVs are typically designed and developed with parts or components that operates through the use of high voltageelectrical systems ranging from 100 Volts to 600 Volts. Also, these type of vehicles have an in-built HEV batteries which are typically encased in sealed shells so as to mitigate potential hazards to a technician.
On the other hand, conventional gasoline vehicles are typically designed and developed with parts or components that operates on hydrocarbon such as fuel and motor engine oil. Also, conventional gasoline vehicles do not require the use of high voltage electrical systems and as such poses less threat to technicians, which is in contrast with hybrid electric vehicles (HEVs) or EVs.
This ultimately implies that, the safety risks for technicians who work on hybrid electric vehicles (HEVs) or EVs are different from those who work on conventional gasoline vehicles due to high voltage electrical systems that are being used in the former.
In conclusion, technicians who work on hybrid electric vehicles (HEVs) or EVs are susceptible (vulnerable) to being electrocuted to death when safety risks are not properly adhered to unlike technicians working on conventional gasoline vehicles.
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Answer:
Batteries are safe when handled properly.
Explanation:
Just like the battery in your phone, the battery in some variant of an electric car is just as safe. If you puncture/smash just about any common kind of charged battery, it will combust. As long as you don't plan on doing anything extreme with the battery (or messing with high voltage) you should be fine.
Answer:
The output will be (3, 4) becomes (8, 10)
Explanation:
#include <stdio.h>
//If you send a pointer to a int, you are allowing the contents of that int to change.
void CoordTransform(int xVal,int yVal,int* xNew,int* yNew){
*xNew = (xVal+1)*2;
*yNew = (yVal+1)*2;
}
int main(void) {
int xValNew = 0;
int yValNew = 0;
CoordTransform(3, 4, &xValNew, &yValNew);
printf("(3, 4) becomes (%d, %d)\n", xValNew, yValNew);
return 0;
}
Answer:
//Annual calendar
#include <iostream>
#include <string>
#include <iomanip>
void month(int numDays, int day)
{
int i;
string weekDays[] = {"Su", "Mo", "Tu", "We", "Th", "Fr", "Sa"};
// Header print
cout << "\n----------------------\n";
for(i=0; i<7; i++)
{
cout << left << setw(1) << weekDays[i];
cout << left << setw(1) << "|";
}
cout << left << setw(1) << "|";
cout << "\n----------------------\n";
int firstDay = day-1;
//Space print
for(int i=1; i< firstDay; i++)
cout << left << setw(1) << "|" << setw(2) << " ";
int cellCnt = 0;
// Iteration of days
for(int i=1; i<=numDays; i++)
{
//Output days
cout << left << setw(1) << "|" << setw(2) << i;
cellCnt += 1;
// New line
if ((i + firstDay-1) % 7 == 0)
{
cout << left << setw(1) << "|";
cout << "\n----------------------\n";
cellCnt = 0;
}
}
// Empty cell print
if (cellCnt != 0)
{
// For printing spaces
for(int i=1; i<7-cellCnt+2; i++)
cout << left << setw(1) << "|" << setw(2) << " ";
cout << "\n----------------------\n";
}
}
int main()
{
int i, day=1;
int yearly[12][2] = {{1,31},{2,28},{3,31},{4,30},{5,31},{6,30},{7,31},{8,31},{9,30},{10,31},{11,30},{12,31}};
string months[] = {"January",
"February",
"March",
"April",
"May",
"June",
"July",
"August",
"September",
"October",
"November",
"December"};
for(i=0; i<12; i++)
{
//Monthly printing
cout << "\n Month: " << months[i] << "\n";
month(yearly[i][1], day);
if(day==7)
{
day = 1;
}
else
{
day = day + 1;
}
cout << "\n";
}
return 0;
}
//end
Fluorescent lamps
Mercury-containing lamps
All of the above
Answer: D all above
Explanation:
Jus done it
Answer:
The critical depth of the rectangular channel is approximately 1.790 meters.
The flow velocity in the rectangular channel is 4.190 meters per second.
Explanation:
From Open Channel Theory we know that critical depth of the rectangular channel (), measured in meters, is calculated by using this equation:
(Eq. 1)
Where:
- Volume flow rate, measured in cubic meters per second.
- Gravitational acceleration, measured in meters per square second.
- Channel width, measured in meters.
If we know that ,
and
, then the critical depth is:
The critical depth of the rectangular channel is approximately 1.790 meters.
Lastly, the flow velocity (), measured in meters, is obtained from this formula:
(Eq. 2)
If we know that ,
and
, then the flow velocity in the rectangular channel is:
The flow velocity in the rectangular channel is 4.190 meters per second.
Answer:
A = 5
S<L, L = 714.89ft
S>L, L = 650.29ft
L = 115.85ft
Percentage min. Length of curvature = 6.2 %
Explanation: see explanation at the attached file
Answer:
Explanation:
effective delay = delay when no traffic x
effective delay =