PHYSICS HIGH SCHOOL

The free-fall acceleration at the surface of planet 1 is 15 m/s2. The radius and the mass of planet 2 are twice those of planet 1. Part A What is g on planet 2

Answers

Answer 1

Answer:

Answer:

3.75m/s²

Explanation:

g= GM/r²

For planet 1

$g_(1)$ = GM/r² (i)

$g_(1)$ = 15m/s²

for planet 2

radius= 2*r= 2r

g= GM/r

$g_(2)$ = GM/(2r)²

$g_(2)$ = GM/4r²

$g_(2)$ = GM/r² *1/4

from (i)

$g_(2)$ = $g_(1)$ *1/4

$g_(2)$ = 15/4

$g_(2)$ = 3.75m/s²

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The amplitude of a transverse wave on a string is 3.0 cm. The ratio of the maximum particle speed to the speed of the wave is 3.9. What is the wavelength (in cm) of the wave?

Answers

Answer:

Therefore the wavelength of the particle is 4.83 m.

Explanation:

Transverse wave: A transverse wave is a moving wave whose direction of wave and oscillation are perpendicular to each other.

Amplitude:The amplitude of a wave is the maximum the distance from its rest position covered by a particle.

Here amplitude (A) = 3.0 cm

The ratio of maximum speed to the speed of the particle is 3.9

The maximum speed of the particle $C_(max)$ = A×ω

The speed of the particle C= f×λ

Then,

$(C_max)/(C) =(A* \omega)/(f* \lambda)$

$\Rightarrow (C_max)/(C) =(A* 2\pi * f)/(f* \lambda)$ [∵ω=2πf]

$\Rightarrow (C_max)/(C) =(A* 2\pi )/( \lambda)$

$\Rightarrow 3.9=(3* 2\pi )/( \lambda)$

$\Rightarrow \lambda=(3* 2\pi )/( 3.9)$

$\Rightarrow \lambda = 4.83$ m

Therefore the wavelength of the particle is 4.83 m

A coil of insulated wire is wound many times around an iron bar. The wire is connected to a battery and a contact switch. The contact switch is alternately flipped closed and left closed, so the wire carries a current through it, and then flipped open and left open, so that the current stops. Describe what magnetic fields are created, if those magnetic fields in turn induce an emf, and whether the induced emf is in the direction of the original current or opposite to it. Justify your answer using Lenz's law and the conditions which can cause a magnetic field to induce an emf. You may draw a diagram if it helps you to visualize the apparatus.

Answers

Answer:

As per faraday's law the rate of change in magnetic flux linked with a coil will induce EMF in the coil. It is given by

$E = - (d\phi)/(dt)$

now here as we are closing the switch and then open it alternatively so it will change the value of current in the coil.

This change in current will change the magnetic flux in the coil due to which it will induce EMF in it.

Now by Lenz the the direction of induce current in the coil will always opposite to the causes due to which it is induced.

As we know that when switch is connected to flow the current the direction of induced current is in opposite to the current so that it will oppose the increasing value of current while when we open the switch the induced current is in direction of the current so that it will increase the value of decreasing current in the loop.

The induced emf is in the direction opposite to the direction of current.

What is induced emf?

Emf is the production of a potential difference in a coil as a result of changes in the magnetic flux passing through it.

When the flux coupling with a conductor or coil changes, electromotive Force, or EMF, is said to be induced.

The rate of change in magnetic flux linked to a coil will induce EMF in the coil, according to Faraday's law.

Now, when we alternately close and open the switch, the current in the coil will change.The magnetic flux in the coil will vary as a result of the change in current, resulting in EMF in the coil.

Now, according to Lenz, the direction of induce current in the coil will always be the polar opposite of the causes.

Hence the induced emf is in the direction opposite to the direction of current.

To learn more about the induced emf, refer to the link;

brainly.com/question/16764848

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What are the different types of energy stores and what they do?

Answers

Kinetic Energy is found in movement.
Potential Energy is any type of stored energy. It can be chemical, nuclear, gravitational, or mechanical.

Answer:

Stores of energy

kinetic energy.

internal energy.

elastic potential energy.

gravitational potential energy.

electrical energy.

magnetic energy.

Explanation:

sana nakatulong)):

Which one of the following lines best illustrates personification? A.She floated graceful as a dove

B.Spring is a dream unsung

C.A narrow wind complains all day

D.The fog comes on little cat feet

Answers

C. A narrow wind complains all day.

Personification is a figure of speech wherein animals, objects, and ideas are given human traits or characteristics.

The narrow wind, which is an unseen object, was given a human trait which is complains.

The lines that best illustrates personification is (D), The fog comes on little cat feet.

What is personification?

Personification is a literary device where inanimate objects are given human qualities. In the line "The fog comes on little cat feet," the fog is given the human qualities of walking and having feet. This is a clear example of personification.

The other lines do not illustrate personification. In line A, "She floated graceful as a dove," the dove is being compared to a graceful woman, but the dove is not being given any human qualities. In line B, "Spring is a dream unsung," spring is being compared to a dream, but spring is not being given any human qualities. In line C, "A narrow wind complains all day," the wind is being compared to a person who is complaining, but the wind is not being given any human qualities.

Find out more on personification here: brainly.com/question/23487716

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1 poinWhat exercise could you do that works on cardiovascular endurance and
muscular strength?*
Bicep Curls
Dips
Stairs
Squats
O Other:

Answers

stairs!

stairs are a great cardiovascular endurance exercise, and also help muscular strength in the legs and core.

hope this helps!

Which phenomenon provides evidence that light has a wave nature?

Answers

Hi Beck

The answer should be

Diffraction of light passing through a narrow opening

I hope that's help :)

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A 25.6-kg child pulls a 4.81-kg toboggan up a hill inclined at 25.7° to the horizontal. The vertical height of the hill is 27.3 m. Friction is negligible.(a) Determine how much work the child must do on the toboggan to pull it at constant velocity up the hill. (b) Repeat (a) if the vertical height is still 27.3 m, but the angle is 19.6°. What general conclusion can you make? (c) The child now slides down the hill on the toboggan. Determine the total work on the child and toboggan during the slide.