Answer:
Alpha centauri will be brighter than Alpha Crucis .
Explanation:
Apparent magnitude of a star measures how bright a star is .
This scale is reverse logarithmic ie , the brighter the star , the lower is its magnitude . A magnitude equal to 5 scale higher represents less magnitude by a factor of 1/ 100 . In this way a difference of 1 magnitude represents a brightness ratio of 2.512 . Hence a star of brightness magnitude of 7 is less bright by a factor 2.512 than that of a star magnitude of 6 .
b. The products of chemical reactions are more stable at higher concentrations.
c. At higher concentrations, reactant molecules move more quickly.
d. At higher concentrations, product molecules are able to catalyze the reaction.
Answer:
The increased concentration increases the number of collisions between molecules.
Explanation:
I just took the test. Flvs
The model of the atom that has electrons traveling in specific paths around the nucleus is Rutherford's model.
Therefore, the correct answer is option B
J. J Thomson proposed that the atom is a sphere of positively charged matter in which negatively charged electron are embedded.
In Rutherford's model of atomic structure, the electrons moves in orbits by electrostatic attraction to the positively charged nucleus.
According to Dalton's atomic theory, atom were indestructible and indivisible solid particle.
Bohr's model made assumption that electron can only exist in circular orbits of definite quantum energy.
According to the question, the model of the atom that has electrons traveling in specific paths around the nucleus is Rutherford's model.
Therefore, the correct answer is option B
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Answer:
A, Bohr's model
Explanation:
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(The other three did have something to do with it they just didn't create that specific model)
V = Volume of sample of gas = 1.00 L = 0.001 m³
T = temperature of the gas = 25.0 ⁰C = 25 + 273 = 298 K
P = pressure = 1.00 atm = 101325 Pa
n = number of moles of gas
using ideal gas equation
PV = n RT
101325 (0.001) = n (8.314) (298)
n = 0.041
n₁ = number of moles of helium
n₂ = number of moles of neon
m₁ = mass of helium = n₁ (4) = 4 n₁
m₂ = mass of neon = n₂ (20.2) = 20.2 n₂
given that :
m₁ = m₂
4 n₁ = 20.2 n₂
n₁ = 5.05 n₂
also
n₁ + n₂ = n
5.05 n₂ + n₂ = 0.041
n₂ = 0.0068
mole fraction of neon is given as
mole fraction = n₂ /n = 0.0068/0.041 = 0.166
P₂ = partial pressure of neon = (mole fraction) P
P₂ = (0.166) (1)
P₂ = 0.166 atm
The partial pressure of the neon is 0.16 atm.
A 1.00 l sample of a gas at 25.0◦c and 1.00 atm contains 50.0 % helium and 50.0 % neon by mass. what is the partial pressure of the neon. express your answer in atmospheres.
The partial pressure is the notional pressure of constituent gas if it is occupied alone by the entire volume of the original mixture at the same temperature.
50.0 % helium and 50.0 % neon by mass.
Mass of the gases =
By using ideal gas equation we get:
where total number of moles of gases
Then we can find the mass and mole of gases
The gas molar volume is the volume of one mole of the gas at a given temperature and pressure.
Mass of helium gas =
Moles of helium gas
Mass of neon gas
Moles of neon gas
Partial pressure of the neon gas:
Therefore the partial pressure of the neon gas is 0.16 atm.
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By the way, on the Penn Foster test, C. 1,254.4 meters is incorrect.