Answer:
f(1/3) = 6
Step-by-step explanation:
f(x) =-3x+7
Let x = 1/3
f(1/3) =-3*1/3+7
= -1 +7
= 6
Answer:
f(1/3) = 6
Step-by-step explanation:
The function is:
● f(x) = -3x+7
Replace x by 1/3 to khow the value of f(1/3)
● f(1/3) = -3×(1/3) +7 = -1 +7 = 6
Answer:
4/9 is left over.
Step-by-step explanation:
First make the denominators the same. 2/3=6/9. 6/9-2/9=4/9.
Answer:
See the attached picture for detailed answer.
Step-by-step explanation:
See the attached picture for detailed answer.
The probability question from part (a) requires calculating the chance of getting all heads or all tails on multiple days in a year, which involves complex probability distributions. For part (b), using a Poisson distribution could be appropriate due to the rarity of the event and the high number of trials involved.
The question pertains to the field of probability theory and involves calculating the probability of specific outcomes when flipping a fair coin. For part (a), Jack flips a coin ten times each morning for a year, counting the days (X) when all flips are identical (all heads or all tails). The exact expression for P(X > 1), the probability of more than one such day, requires several steps. First, we find the probability of a single day having all heads or all tails, then use that to calculate the probability for multiple days within the year. For part (b), whether it is appropriate to approximate X by a Poisson distribution depends on the rarity of the event in question and the number of trials. A Poisson distribution is typically used for rare events over many trials, which may apply here.
For part (a), the probability on any given day is the sum of the probabilities of all heads or all tails: 2*(0.5^10). Over a year (365 days), we need to calculate the probability distribution for this outcome occurring on multiple days. To find P(X > 1), we would need to use the binomial distribution and subtract the probability of the event not occurring at all (P(X=0)) and occurring exactly once (P(X=1)) from 1. However, this calculation can become quite complex due to the large number of trials.
For part (b), given the low probability of the event (all heads or all tails) and the high number of trials (365), a Poisson distribution may be an appropriate approximation. The mean (λ) for the Poisson distribution would be the expected number of times the event occurs in a year. Since the probability of all heads or all tails is low, it can be considered a rare event, and the Poisson distribution is often used for modeling such scenarios.
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Write an equation to represent the image.
Answer: 3p=1/2
Just do it right now
Answer:
Step-by-step explanation:
Given that ball is thrown vertically with intial velocity 80 ft per second at a height of 15 feet off the ground.
Let angle of the ball thrown with horizontal be A
Then vertical velocity = 80 sinA
HOrizontal velocity = 80 cosA
Acceleration here is negative gravity
In fps system gravity g = -32ft/sec^2
s=ut+1/2at^2
Substitute to get
h(t) = 80cos A t-16t^2 +15 (since initial height is 15 ft)
x(t) = 80 sin A t
8x=4x−32
A)x = 8
B)x = 4
C) x=−4
D) x=−8
Answer:
x=-8
Step-by-step explanation:
i took the quiz
Answerd
Step-by-step explanation:
Find the value of k.
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Explanation:
We're going to be using the slope formula a bunch of times.
Find the slope of the line through points A and C
m = (y2 - y1)/(x2 - x1)
m = (-12-9)/(9-2)
m = -21/7
m = -3
The slope of line AC is -3. The slopes of line AB and line BC must also be the same for points A,B,C to be collinear. The term collinear means all three points fall on the same straight line.
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Let's find the expression for the slope of line AB in terms of k
m = (y2 - y1)/(x2 - x1)
m = (k-9)/(4-2)
m = (k-9)/2
Set this equal to the desired slope -3 and solve for k
(k-9)/2 = -3
k-9 = 2*(-3) ..... multiply both sides by 2
k-9 = -6
k = -6+9 .... add 9 to both sides
k = 3
If k = 3, then B(4,k) updates to B(4,3)
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Let's find the slope of the line through A(2,9) and B(4,3)
m = (y2 - y1)/(x2 - x1)
m = (3-9)/(4-2)
m = -6/2
m = -3 we get the proper slope value
Finally let's check to see if line BC also has slope -3
m = (y2 - y1)/(x2 - x1)
m = (-12-3)/(9-4)
m = -15/5
m = -3 we get the same value as well
Since we have found lines AB, BC and AC all have slope -3, we have proven that A,B,C fall on the same straight line. Therefore, this shows A,B,C are collinear.