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Find an exact value of sin(17pi/12)

Answers

Answer 1

Answer:

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Hi my lil bunny!

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$((17)(3.141593))/(12)$

= $(53.407075)/(12)$

= $4.45059$

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If this helped you, could you maybe give brainliest..?

Also Have a great day/night!

❀*May*❀

Answer 2

Answer:

I have an answer and explanation but I can't type so search up the question you asked and you should get an answer and explanation from s0cratic.

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Write a linear equation in standard form for the following scenario Matt is in charge of selling roses and chocolate hearts for the Valentine's Day dance he sell Beats Rose for $5 I need to Chocolate hard for $2.50 at the end of the dance he made a total of $250*

Answers

50 beats rose chocolate
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Does sine inverse have an exponent? If not, why is there a negative one there? If so, why can't you just divide?

Answers

Answer:

see below

Step-by-step explanation:

the actual way of writing sin inverse is arcsine, not sin⁻¹

since the output of sin is from -1 to 1, the domain of arsince is from -1 to 1. This is different than 1/sin(x), whose domain is all real numbers. we now write sin⁻¹ to fit it on the tiny buttons on our calculators

A rock thrown vertically upward from the surface of the moon at a velocity of 36m/sec reaches a height of s = 36t - 0.8 t^2 meters in t sec.a. Find the rock's velocity and acceleration at time t.
b. How long does it take the rock to reach its highest point?
c. How high does the rock go?
d. How long does it take the rock to reach half its maximum height?
e. How long is the rock a loft?

Answers

Answer:

a. The rock's velocity is $v(t)=36-1.6t \:{(m/s)}$ and the acceleration is $a(t)=-1.6 \:{(m/s^2)}$

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

Velocity is defined as the rate of change of position or the rate of displacement. $v(t)=(ds)/(dt)$
Acceleration is defined as the rate of change of velocity. $a(t)=(dv)/(dt)$

The rock's velocity is the derivative of the height function $s(t) = 36t - 0.8 t^2$

$v(t)=(d)/(dt)(36t - 0.8 t^2) \n\n\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\n\nv(t)=(d)/(dt)\left(36t\right)-(d)/(dt)\left(0.8t^2\right)\n\nv(t)=36-1.6t$

The rock's acceleration is the derivative of the velocity function $v(t)=36-1.6t$

$a(t)=(d)/(dt)(36-1.6t)\n\na(t)=-1.6$

b. The rock will reach its highest point when the velocity becomes zero.

$v(t)=36-1.6t=0\n36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\n360-16t=0\n360-16t-360=0-360\n-16t=-360\nt=(45)/(2)=22.5$

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

$s(22.5) = 36(22.5) - 0.8 (22.5)^2\ns(22.5) =405$

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = $(405)/(2) =202.5 \:m$

To find the time it reach half its maximum height, we need to solve

$36t - 0.8 t^2=202.5\n36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\n360t-8t^2=2025\n360t-8t^2-2025=2025-2025\n-8t^2+360t-2025=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are

$x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)$

$\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\n\nt=(-360+√(360^2-4\left(-8\right)\left(-2025\right)))/(2\left(-8\right))=(45\left(2-√(2)\right))/(4)\approx 6.59\n\nt=(-360-√(360^2-4\left(-8\right)\left(-2025\right)))/(2\left(-8\right))=(45\left(2+√(2)\right))/(4)\approx 38.41$

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

$36t - 0.8 t^2=0\n\n\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\n\n\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\n\nt=0,\:t=45$

The rock is aloft for 45 seconds.

When line sets have been altered, they may not be treated as self-contained systems of their own?

Answers

First of all, you may alter line sets. When you do, the nitrogen charge is released into the atmosphere.
You can then pressure the lines with a tracing gas in order to check if there are leaks in the connections you've made.
After the test is complete, you have to evacuate the line set before opening the valves to start the system.

Knowing this, we can say that line sets, when altered, may NOT be treated as self-contained systems of their own is a FALSE statement.

300 people joined the community orchestra. Some intended to play a string instrument, some a brass instrument, and the others percussion. If 3 times as many people were planning to play a string instrument as a brass instrument, and if 60 fewer were going to play percussion than a brass instrument, how many people were planning to play each type of instrument?

Answers

Total amount of instrument players= 300
Number of brass instrument players= x (because we do not know how many there are, except that all other values that we must calculate are based off of the number of brass players we have
Number of string instruments= 3x (because 3 times more than the number of brass instruments
Number of Percussion= x-60 (because there are 60 less percussion players than brass players

So, our equation is (number of string instruments)+(number of brass instruments)+(number of percussion instruments)=300 (which is our total possible number of people

3x+x+x-60=300
3x+x+x=360
5x=360
x= 72

We have 72 brass instrument players, 3(72)= 216 string instrument players, and 72-60=12 percussion players

check: 72+216+12=300

Someone help pls!!! Thanks

Answers

Answer:

The answers are A and C

Step-by-step explanation:

A is correct because -16 is on the left of the number line.

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