Multiply 5/48 times 24/51 in simplest form

Answers

Answer 1
Answer: 5/102 is the answer in simplest form.
Answer 2
Answer: The answer is 120/2448
or if simplest form
12/204
6/102
3/51
1/17

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Which equation describes the line that contains (1,5) and has a slope of 2

Answers

The equation that describes the line that contains (1,5) and has a slope of 2 is y = 3x + 2

The equation of a line in point slope form is expressed as;

  • y-y0 = m(x - x0)

  • m is the slope of the line
  • (x0, y0) is the point on the line

Given the following parameters;

Slope  = 2

Point on the line is (1, 5)

Substitute the given parameters into the formula to have:

y - 5 = 3(x-1)

y - 5 = 3x - 3

y = 3x + 2

Hence the equation that describes the line that contains (1,5) and has a slope of 2 is y = 3x + 2

Learn more on equation of a line here: brainly.com/question/18831322

in order to write an equation you need to find the y-intercept. the way you do this is by plugging in the value 2 and the point into y=mx+b and solving for b. once you plug everything in you get 5=2(1)+b. solving from here you get b=3. putting everything together you get y=2x+3

An Axiom in Euclidean geometry states that in space, there are at least three points that do

Answers

Answer:

...not lie on the same plane.

Step-by-step explanation:

Answer two questions about Equations AAA and BBB:\begin{aligned} A.&&4x+2&=6-x \\\\ B.&&5x+2&=6 \end{aligned}
A.4x+2=6−x
B.5x+2=6


1) How can we get Equation B from Equation A?
Choose 1 answer:


(Choice A)
A
Add/subtract a quantity to/from only one side

(Choice B)
B
Add/subtract the same quantity to/from both sides

(Choice C)
C
Multiply/divide only one side by a non-zero constant

(Choice D)
D
Multiply/divide both sides by the same non-zero constant
2) Based on the previous answer, are the equations equivalent? In other words, do they have the same solution?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
Yes

(Choice B)
B
No

Answers

Answer:

answer is d

Step-by-step explanation:

Answer:

A AND B

Step-by-step explanation:

They both have the same solution

Which of the following functions has the greatest y-intercept?f(x)

x y
−3 −15
−2 −8
−1 −1
0 3
1 6
2 10
g(x) = −4 sin(5x) + 3

Answers

The y intercept occurs when x = 0

So for first function y-intercept = 3.

Second function:-

y intercept = -4 sin (5*0) + 3

= -4(0) + 3 = 3

y - intercepts are equal.

Pls help with number 16...

Answers

a. Area of a square= side length squared
=> A= (x-3)^2
= x^2-6x+9
b. Area of rectangle= larger side length* smaller side length
=> A= x(x-5)
= x^2-5x
c. If both areas equal then expressions for areas equal as well.
x^2-5x= x^2-6x+9
=>x=9

Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas. He starts by assigning coordinates as given.A right triangle is graphed on a coordinate plane. The horizontal x-axis and y-axis are solid, and the grid is hidden. The vertices are labeled as M, K, and L. The vertex labeled as M lies on begin ordered pair 0 comma 0 end ordered pair. The vertex labeled as K lies on begin ordered pair 0 comma 2 b end ordered pair. The vertex labeled as L lies on begin ordered pair 2a comma 0 end ordered pair. A bisector is drawn from point M to the line KL. The intersection point on line KL is labeled as N.

Enter the answers to complete the coordinate proof.
N is the midpoint of KL¯¯¯¯¯KL¯ . Therefore, the coordinates of N are (a,
).

To find the area of △KNM△KNM , the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM△KNM is
.

To find the area of △MNL△MNL , the length of the base ML is
, and the length of the height is
. So an expression for the area of △MNL△MNL is ab.

Comparing the expressions for the areas shows that the areas of the triangles are equal.

Answers

The coordinates of N is (a,b) using the midpoint formula.
The area for △KNM is (1/2)(a)(2b) = ab
The area of △MNL is ab.
Since the area of 
△KNM = △MNL and the area of △KML is 2ab, then we have proved that a segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

1. N is a midpoint of the segment KL, then N has coordinates

\left((x_K+x_L)/(2),(y_K+y_L)/(2) \right) =\left((0+2a)/(2),(2b+0)/(2) \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_(KMN)=(1)/(2)\cdot \text{base}\cdot \text{height}=(1)/(2)\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_(MNL)=(1)/(2)\cdot \text{base}\cdot \text{height}=(1)/(2)\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_(KMN) is equal to the area A_(MNL). This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.