The equation that describes the line that contains (1,5) and has a slope of 2 is y = 3x + 2
The equation of a line in point slope form is expressed as;
Given the following parameters;
Slope = 2
Point on the line is (1, 5)
Substitute the given parameters into the formula to have:
y - 5 = 3(x-1)
y - 5 = 3x - 3
y = 3x + 2
Hence the equation that describes the line that contains (1,5) and has a slope of 2 is y = 3x + 2
Learn more on equation of a line here: brainly.com/question/18831322
Answer:
...not lie on the same plane.
Step-by-step explanation:
A.4x+2=6−x
B.5x+2=6
1) How can we get Equation B from Equation A?
Choose 1 answer:
(Choice A)
A
Add/subtract a quantity to/from only one side
(Choice B)
B
Add/subtract the same quantity to/from both sides
(Choice C)
C
Multiply/divide only one side by a non-zero constant
(Choice D)
D
Multiply/divide both sides by the same non-zero constant
2) Based on the previous answer, are the equations equivalent? In other words, do they have the same solution?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
Yes
(Choice B)
B
No
Answer:
answer is d
Step-by-step explanation:
Answer:
A AND B
Step-by-step explanation:
They both have the same solution
x y
−3 −15
−2 −8
−1 −1
0 3
1 6
2 10
g(x) = −4 sin(5x) + 3
The y intercept occurs when x = 0
So for first function y-intercept = 3.
Second function:-
y intercept = -4 sin (5*0) + 3
= -4(0) + 3 = 3
y - intercepts are equal.
Enter the answers to complete the coordinate proof.
N is the midpoint of KL¯¯¯¯¯KL¯ . Therefore, the coordinates of N are (a,
).
To find the area of △KNM△KNM , the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM△KNM is
.
To find the area of △MNL△MNL , the length of the base ML is
, and the length of the height is
. So an expression for the area of △MNL△MNL is ab.
Comparing the expressions for the areas shows that the areas of the triangles are equal.
1. N is a midpoint of the segment KL, then N has coordinates
2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is
3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is
4. Comparing the expressions for the areas you have that the area is equal to the area . This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.