MATHEMATICS HIGH SCHOOL

A una granja llegaron 54 ovejas 24 vacas 30 cerdos los cuales se quieren repartir en corrales con igual numero de animales de forma que haya la mayor cantidad posible en cada corral ¿cuantos animales posibles deben ir en cada uno de los corrales?

Answers

Answer 1
Answer:

Answer: 6 animals should go in each pen.

Step-by-step explanation:

Total sheep = 54

Total cows = 24

Total pigs = 30

Highest number of animals are possible in each pen such that animals are distributed in pens with the same number = Greatest common divisior (54,24, 30)

54= 6 x 9

24= 6 x 4

30 = 6 x 5

So, Greatest common divisior (54,24, 30) = 6

Hence, 6 animals should go in each pen.

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Answers

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The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms.How long will it take for the population of the bacteria to reach 800?

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Answers

Answer:

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Step-by-step explanation:

population 2x in 24 h

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Solve using elimination, 2x+5y=2   3x-5y=53

Answers

      2x + 5y =2
 (+) 3x - 5y =53
-------------------------
      5x + 0 = 55

Then finish it.

5x = 55
x = 11

Substitute x = 11, 

2(11) + 5y = 2
22 - 2 + 5y = 0
20 + 5y = 0
5y = -20
y= -4
2x+5y=2
3x-5y=53
---------------
+
2x+3x=2+53
5x=55 / : 5
x=11

x=11
3x-5y=53

x=11
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x=11
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x=11
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x=11
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