x= -4 y=16-5=11
x= -2 y=4-5= -1
x= -1 y=1-5= -4
x= 0 y= -5
x= 1 y= 1-5= -4
x= 2 y=4-5= -1
x=3 y=9-5=4
x=4 y=16-5=11
B. (x-3)^2+(y+2)^2=1.5
C. (x+3)^2+(y-2)^2=2.25
D. (x-3)^2+(y+2)^2=2.25
the answer is D i just took the test
A.
The student mislabeled the work in the second step as "Addition property of equality."
B.
The student improperly applied the addition property of equality in the second step.
C.
The student computed the sums improperly to arrive at an erroneous answer in step 3.
(D.
There is no error. The student's justification is correct.)
B) $91.43¢/qt
C) 64¢/qt
D) 0.64¢/qt
answer:
b. $91.43/qt
step-by-step explanation:
it's a lot of work
O 55 cm²
O 99 cm²
O220 cm²
D4 cm F 11 cm 1 I A 5 cm E4 cm B 5 cm C
The calculated value of the area of the parallelogram is 99 square cm
From the question, we have the following parameters that can be used in our computation:
The parallelogram
Where we have
Height = 11 cm
Base = 5 cm + 4 cm = 9 cm
The area of the parallelogram is calculated as
Area = Base * Height
Substitute the known values in the above equation, so, we have the following representation
Area = 11 * 9
Evaluate the product of 11 and 9
So, we have the following representation
Area = 99
Hence, the area of the parallelogram is 99 square cm
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