David says he has 2/3 of a pipe length​ left, while Don says he has 11/16 of a length left. Which person has the longest section​ left?

Answers

Answer 1
Answer:

Don has the longest section of pipe because the fraction number 11/16 is greater than the fraction number 2/3.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The decimal number is the sum of a whole number and part of a fraction number. The fraction number is greater than zero but less than one.

David says he has 2/3 of a line length left, while Wear says he has 11/16 of a length left.

Convert the fraction numbers 2/3 and 11/16 into the decimal number. Then we have

2/3 = 0.6667

11/16 = 0.6875

The decimal number 0.6875 is greater than 0.6667. Then the fraction number 11/16 is greater than the fraction number 2/3.

Don has the longest section of pipe because the fraction number 11/16 is greater than the fraction number 2/3.

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ2

Answer 2
Answer:

Answer:

Don

Step-by-step explanation:

1. We make the fractions have common denominators so it is easier to compare them. We can do this buy multiplying 2/3 by a factor of 16, so it becomes 32/48. For 11/16, we multiply by a factor of 3 so it becomes 33/48. It is now apparent that Don has the longer pipe.


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Throughout the US presidential election of 2012, polls gave regular updates on the sample proportion supporting each candidate and the margin of error for the estimates. This attempt to predict the outcome of an election is a common use of polls. In each case below, the proportion of voters who intend to vote for each candidate is given as well as a margin of error for the estimates. Indicate whether we can be relatively confident that candidate A would win if the election were held at the time of the poll. (Assume the candidate who gets more than of the vote wins.)

Answers

Answer:

1.) We cannot say for certain which candidate will win. But A has a statistical edge.

2.) We can say certainly that candidate A will win the election; albeit with a not so big margin.

3.) Candidate A will win this election based on the results of the final poll's before the election.

4.) We cannot say for certain which candidate will win. But A has a statistical edge.

The reasons are explained below.

Step-by-step explanation:

Confidence interval expresses a range of values in the distribution where the true proportion or mean can be found with some level of confidence.

Confidence Interval = (Sample Mean or Proportion) ± (Margin of error)

1. Candidate A: 54% & Candidate B:46% with Margin of error: + 5%

The confidence interval for candidate A

(54%) ± (5%) = (49%, 59%)

The confidence interval for candidate B

(46%) ± (5%) = (41%, 51%)

Since values greater than 50% occur in both intervals, we cannot say for certain that either of the two candidates will outrightly win the election. It just slightly favours candidate A who has A bigger range of confidence interval over 50% for the true sample proportion to exist in.

2. Candidate A: 52% & Candidate B:48% with Margin of error: + 1%

The confidence interval for candidate A

(52%) ± (1%) = (51%, 53%)

The confidence interval for candidate B

(48%) ± (1%) = (47%, 49%)

Here, it is outrightly evident that candidate A will win the elections based on the result of the final polls. The overall range of the confidence interval that contains the true sample proportion of voters that support candidate A is totally contained in a region that is above 50%. So, candidate A wins this one, easily; albeit with a close margin though.

3. Candidate A: 53% & Candidate B:47% with Margin of error: + 2%

The confidence interval for candidate A

(53%) ± (2%) = (51%, 55%)

The confidence interval for candidate B

(47%) ± (2%) = (45%, 49%)

Here too, it is outrightly evident that candidate A will win the elections based on the result of the final polls. The overall range of the confidence interval that contains the true sample proportion of voters that support candidate A is totally contained in a region that is above 50%. Hence, statistics predicts that candidate A wins this one.

4. Candidate A: 58% & Candidate B:42% with Margin of error: + 10%

The confidence interval for candidate A

(58%) ± (10%) = (48%, 68%)

The confidence interval for candidate B

(42%) ± (10%) = (32%, 52%)

Since values greater than 50% occur in both intervals, we cannot say for certain that either of the two candidates will outrightly win the election. It just slightly favours candidate A who has A bigger range of confidence interval over 50% for the true sample proportion to exist in.

Hope this Helps!!!

In one full day, a kudzu vine can grow 15 inches in length. How many inches per hour is this?

Answers

1.66666666667 inches per hour

Answer:

0.625

Step-by-step explanation:

15 divided by 24 which equals 0.625

Gabrielle is 10 years older than mike. the sum of their ages is 56. how old is mike

Answers

Answer: 23

Step-by-step explanation:

Let

m be Mike's age.

According to the given information, Gabrielle is

+

10

m+10 years old.

The sum of their ages is given by:

+

(

+

10

)

=

56

m+(m+10)=56

Combining like terms, we get:

2

+

10

=

56

2m+10=56

Subtracting 10 from both sides, we have:

2

=

46

2m=46

Dividing both sides by 2, we get:

=

23

m=23

So, Mike is 23 years old.

mike is 23 years old

Consider a home mortgage of $250,000 at a fixed APR of 4.5% for 25 years.a. Calculate the monthly payment.
b. Determine the total amount paid over the term of the loan.
c. Of the total amount paid, what percentage is paid toward the principal and what
percentage is paid for interest.
a. The monthly payment is $ 1389.58.
(Do not round until the final answer. Then round to the nearest cent as needed.)
b. The total amount paid over the term of the loan is $
(Round to the nearest cent as needed.)
ANSWER ALL PARTS PLEASE (A,B,C)

Answers

ALL THE ANSWERS AND EXPLANATION ARE GIVEN BY CHATGPT LOOK IN THE FILE ATTACHED

Consider the diagram and the proof below.Given: In △ABC, AD ⊥ BC
Prove: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

Triangle A B C is shown. A perpendicular bisector is drawn from point A to point D on side C B forming a right angle. The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.

A 2-column table has 7 rows. The first column is labeled Statement with entries In triangle A B C line segment A D is perpendicular to line segment B C, In triangle A D B sine (uppercase B) = StartFraction h Over c EndFraction, c sine (uppercase B) = h, In triangle A C D, sine (uppercase C) = StartFraction h Over b EndFraction, b sine (uppercase C) = h, question mark, StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction. The second column is labeled Reason with entries given, definition of sine, multiplication property of equality, definition of sine, multiplication property of equality, substitution, and division property of equality.

What is the missing statement in Step 6?

b = c

StartFraction h Over b EndFraction = StartFraction h Over c EndFraction
csin(B) = bsin(C)

bsin(B) = csin(C)

Answers

Answer:

c- the right triangle altitude theorem

Step-by-step explanation:

i did it on edge! ; )

The opening prices per share Y1 and Y2 of two similar stocks are independent random variables, each with a density function given by

Answers

Answer:given by what?