Find the volume o the sphere.
Find the volume o the sphere. - 1

Answers

Answer 1
Answer:

Answer:

The volume of sphere is 267.95 units³.

Step-by-step explanation:

Given that the formula of volume of sphere is V = 4/3×π×r³ where r represents radius. Then, you have to substitute the values into the formula :

v =  (4)/(3)  * \pi *  {r}^(3)

let \: r = 4

v =  (4)/(3)  * \pi *  {4}^(3)

v =  (4)/(3)  * \pi * 64

v =  (256)/(3)  * 3.14

v = 267.95 \:  {units}^( 3)

Answer 2
Answer: V=4/3πr^3
= 4/3 x π x 4^3
= 268.08
= 85.33 π
~ 300 units ^3

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Kevin has 65 feet of fencing. He wants to use all the fencing to create a rectangular fence around his pool. The equation 2L + 2W = 65, where l is the length of the fence and w is the width. If Kevin makes the length of the fence 13 feet long, how wide should he make it?

Answers

19.5 feet long because it’s says 2L so the length he puts it at is 13 feet so you times that by 2 and get 26. Then take 65 minus 26 and you get 39, then take 39 divided by 2 and get 19.5 I think that’s the answer that’s what I would do

Let x = 20. Which expression has a value greater than 4x−10 ? 5x−100 8(x−10) 5(2x−26) 5x−30

Answers

Answer:

  8(x-10)

Step-by-step explanation:

When the calculation is repetitive, I like to let a calculator or spreadsheet do it. The value of the given function is

  4·20 -10 = 70

Only the expression 8(x-10) = 8(20-10) = 80 has a larger value for x=20.

_____

Comment on this solution

It is actually fewer keystrokes to copy the numbers into a calculator, but getting a record of results can be difficult.

Answer:

Step-by-step explanation:

Please help its vocab matching

Answers

Answer:

1. S

2. G

3. I

4. O

5. P

6. D

7. C

8. F

9. J

10. Q

11. E

12. K

13. R

14. A

15. B

16. N

17. M

18. L

19. H

Step-by-step explanation:

4. O

→ 3 is a coefficient of 3x

5. P

→ 3 is a common factor in the expression 3x+9

6. D

→example of a constant term is 1,3,10

7. C

cosx=(adjacent)/(hypotenuse) =(A)/(H)

8. F

x^(2) -4 will be factorised as (x-2)(x+2)

9. J

→ example of an expression is 2x+9

10. Q

→ factors of 3 are 3×1.

11. E

→ example of factoring is (x+2)(3x+4)

12. K

→ example of a factored completely is 2x(x+y)

14. A

→example of a polynomial is 3yx^(3) +xy^(2) -2x+9.

15. B

→ example of a quadratic expression is x^(2) +6x-9.

17. M

sinx=(opposite)/(hypotenuse) =(O)/(H)

18. L

tanx=(opposite)/(adjacent) =(O)/(A)

19. H

→ example of a term is 2x,3,40

What are the advantages of a closed​ question? A. Closed questions allow the respondent to go​ in-depth with their answers. B. It is possible to automate the collection of results for closed questions. C. Closed questions allow for new solutions to be introduced. D. It is easy to quantify and compare the results of surveys with closed questions.

Answers

Answer:

closed questions are questions with fixed answer options

A. Closed questions allow the respondent to go​ in-depth with their answers.

  • no, it is relevant to open questions

B. It is possible to automate the collection of results for closed questions.

  • yes

C. Closed questions allow for new solutions to be introduced.

  • no, it allows to collect statistical data but not good for new solutions, it better works with open questions when new ideas, solutions may appear

D. It is easy to quantify and compare the results of surveys with closed questions.

  • yes

What value of x makes the equation 7^15⋅7^4=7x true?

Answers

Answer:

To find the value of x that makes the equation 7^15 * 7^4 = 7^x true, you can use the properties of exponents.

In this case, you can apply the rule that when you multiply two numbers with the same base, you can add their exponents. So, for the equation:

7^15 * 7^4 = 7^x

You can combine the exponents on the left side:

7^(15 + 4) = 7^x

Now, you have:

7^19 = 7^x

For these two exponential expressions to be equal, the exponents must be equal:

x = 19

So, the value of x that makes the equation true is x = 19.

Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reachvertex 'H' starting from vertex 'A'>

Answers

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}