Consider an optimization model with a number of resource constraints. Each indicates that the amount of the resource used cannot exceed the amount available. Why is the shadow price of such a resource constraint always zero when the amount used in the optimal solution is less than the amount available?

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Answer 1
Answer:

Shadow pricing refers to the practice of accounting the prince of securities not on their assigned market value (as might be expected) but by their amortized costs. This can also be considered an "artificial" price assigned to a non-priced asset or accounting entry.

In this optimization model, we find a number of resource constraints which limit the changes to the resources. It is expected that these resources would not exceed the amount allocated for each particular constraint. The shadow price of a resource constraint would be zero in this example because the amount used would be less than the amount available. This means that it can fit within the established parameters, and therefore, would not need to be assigned a shadow price.


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Answers

Answer:

f(x) = x^2

And we want to scale vertically this parabola by a factor of 7. So then we need to multiply our function by the factor:

g(x) = k f(x)

And then function would be:

g(x) = 7x^2

Step-by-step explanation:

For this case we have the original function given by:

f(x) = x^2

And we want to scale vertically this parabola by a factor of 7. So then we need to multiply our function by the factor:

g(x) = k f(x)

And then function would be:

g(x) = 7x^2

Ashley has two coupons for a phone.Coupon A:
Coupon B:
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$45 rebate on a $65 phone
Choose the coupon that gives the lower price.
Then fill in the blank with the correct value.

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Answers

Answer:

y = x⁴ +4x³ +4x² +4x +3

Step-by-step explanation:

The coefficients of the offered quartics (in order) have 1, 1, 1, and 0 sign changes, respectively. Descartes' rule of signs tells you this means the first three choices all have one (1) positive real root, so the negative real roots -1 and -3 are not the only ones.

The only possible polynomial is the last one. Synthetic division of that polynomial by roots -1 and -3 leave the remaining factor as x²+1, which has only complex zeros.

The appropriate choice is ...

... y = x⁴ +4x³ +4x² +4x +3