Which situation is most likely to have a constant rate of change?
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sssophiaaa avatar

Answers

Answer 1
Answer:

Answer:

the answer i would go with is A

Good luck on your Test :)

Step-by-step explanation:

B doesnt really have a constant rate of change as it depends on how many games happen and usually the longer an arena stays open has no correlation on how many people attend the games there

C has no real constant rate of change as it always ends up stopping after a little bit, and the change is usually not a constant one

D this could count, but since its a number that would go down if its not brought back up, its not a real constant rate of change, since it cant go below or above a certain range

so by process of elimination, A is the answer. also seeing as how its saying the distance with the number of times, that means that its an objective thing, as a track is a set distance, and the distance of a run or the track cant be affected by time or anything and could technically never end. so its a constant thing, meaning the longer the distance is, the higher the laps around the track are, and it could theoretically go on forever.

i hope this helped answer your question! :)

Answer 2
Answer: The answer is the question is most definitely A

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What are 3 careers where similarity is used

Answers

Answer:

Management                Farming                  Construction

Step-by-step explanation:

5. The length of similar components produced by a company are approximated by a normal distribution model with a mean of 5 cm and a standard deviation of 0.02 cm. If a component is chosen at random a) what is the probability that the length of this component is between 4.98 and 5.02 cm

Answers

Answer:

the probability that  he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)

Step-by-step explanation:

Since the random variable X= length of component chosen at random , is normally distributed, we can define the following standardized normal variable Z:

Z= (X- μ)/σ

where μ= mean of X  , σ= standard deviation of X

for a length between 4.98 cm and 5.02 cm , then

Z₁= (X₁- μ)/σ =  (4.98 cm - 5 cm)/0.02 cm = -1

Z₂= (X₂- μ)/σ = (5.02 cm - 5 cm)/0.02 cm = 1

therefore the probability that the length is between 4.98 cm and 5.02 cm is

P( 4.98 cm ≤X≤5.02 cm)=P( -1 ≤Z≤ 1) = P(Z≤1) - P(Z≤-1)

from standard normal distribution tables we find that

P( 4.98 cm ≤X≤5.02 cm) = P(Z≤1) - P(Z≤-1) = 0.841 - 0.159 = 0.682 (68.2%)

therefore the probability that  he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)

Consider △LNM.
Which statements are true for triangle LNM? Check all that apply.

Answers

Answer:

The correct options are 1, 2 and 4.

Step-by-step explanation:

In a triangle, the side which does not make an angle is called opposite side of that angle.

From the given graph it is clear that

Opposite side of ∠L is NM.

Option 1 is correct.

Opposite side of ∠M is NL.

Opposite side of ∠N is ML.

Option 2 is correct.

The side next to an angle is called adjacent side.

Adjacent sides of ∠L is LM and LN.

Adjacent sides of ∠M is LM and MN.

Adjacent sides of ∠N is LN and MN.

In a right angled triangle, the opposite sides of a right angle is called hypotenuse.

Angle M is a right angled, so the side NM is hypotenuse. Option 4 is correct.

Therefore the correct options are 1, 2 and 4.

1 2 and 4 are correct. the others arent

Question 2A square room of side length x is made 5 m longer (its width stays the same). What is the new area
of the room?​

Answers

Answer:

To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

Step-by-step explanation:

The area of any quadrilateral can be determined by multiplying the length of its base by its height. Since we know the shape here is square, we know that all sides are of equal length. From this we can work backwards by taking the square root of the area to find the length of one side. hope this helps you :)

A professor at a university wants to estimate the average number of hours of sleep the students get during exam week. The professor wants to find a sample mean that is within 4.266 hours of the true average for all college students at the university with 99% conconfidence. If the professor knows the standard deviation of the sleep times for all college students is 2.539, what sample size will need to be taken

Answers

Answer:

The sample size is n = 2

Step-by-step explanation:

From the question we are told that

   The margin of error is  E =4.266

    The standard deviation is  \sigma = 2.539

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of  (\alpha )/(2) is  

   Z_{(\alpha )/(2) } =  2.58

Generally the sample size is mathematically represented as  

   n = [\frac{Z_{(\alpha )/(2) } *  \sigma }{E} ] ^2

=>  n = [(2.58  *  2.539  )/(4.266) ] ^2

=>  n = 2

What is 19% of 103?

Answers

Answer:

19.57

Step-by-step explanation:

When you do 19% of 103

you get 19.57

Hope this helps! <3

Answer:  19% of 103 is 19.57

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