In a container of negligible heat capacity, mix 6kg of ice at -40 ° C with 3kg of steam at 120 ° C, determine the equilibrium temperature.
Answers
Answer:
100°C
Explanation:
The heat gained by the ice equals the heat lost by the steam, so the total heat transfer equals 0.
Heat lost by the steam as it cools to 100°C:
q = mCΔT
q = (3 kg) (2.00 kJ/kg/K) (100°C − 120°C)
q = -120 kJ
Total heat so far is negative.
Heat lost by the steam as it condenses:
q = -mL
q = -(3 kg) (2256 kJ/kg)
q = -6768 kJ
Heat absorbed by the ice as it warms to 0°C:
q = mCΔT
q = (6 kg) (2.11 kJ/kg/K) (0°C − (-40°C))
q = 506.4 kJ
Heat absorbed by the ice as it melts:
q = mL
q = (6 kg) (335 kJ/kg)
q = 2010 kJ
Heat absorbed by the water as it warms to 100°C:
q = mCΔT
q = (6 kg) (4.18 kJ/kg/K) (100°C − 0°C)
q = 2508 kJ
The total heat absorbed by the ice by heating it to 100°C is 5024.4 kJ.
If the steam is fully condensed, it loses a total of -6888 kJ.
Therefore, the steam does not fully condense. The equilibrium temperature is therefore 100°C
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if 15 N of force are applied to a cart to move it a distance of 5m, how much work is done on the cart
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In this question we have given
velocity of missile=1350m/s
angle at which missile is moving=25degree
distance between missile and targets=23500m
angle between target and missile=55degree
time=10.2s
To find the final velocity of missile we will first find the acceleration required
Let x be the horizontal component of distance
x - vertical component of distance
t-time
ax- horizontal component of acceleration
ay-Vertical component of acceleration
Vx-horizontal component of velocity
Vy-Vertical component of velocity
horizontally: x = Vx*t + ½*ax*t²
23500m * cos55.0º = 1350m/s * cos25.0º * 10.20s + ½ * ax * (10.20s)²
ax = 19.2 m/s²
V'x = Vx + ax*t = 1350m/s * cos25.0º + 19.2m/s² * 10.20s = 1419 m/s
similarly vertically:
y = Vy*t + ½*ay*t²
23500m * sin55.0º = 1350m/s * sin25.0º * 10.20s + ½ * ay * (10.20s)²
ay = 258 m/s²
V'y = Vy + ay*t = 1350m/s * sin25.0º + 258m/s² * 10.20s = 3204 m/s
Therefore
V = √(V'x² + V'y²) = 3504 m/s
therefore magnitude of final velocity of missile=3504m/s
Answers
1 s=20m
10 s=200m
Final answer:
The maximum distance that a ball can be thrown at a speed of 20 m/s depends on the angle at which the ball is thrown. In ideal conditions and at a 45-degree angle, the theoretical maximum distance is approximately 40.57 meters.
Explanation:
The question is asking about the maximum distance you can throw a ball given an initial speed, which is a topic in Physics known as projectile motion. In an ideal condition, where air resistance is ignored, the maximum distance a projectile can travel is achieved when it is launched at an angle of 45 degrees.
However, we are missing a piece of information in this situation, which is the launch angle. Without knowing the angle at which the ball is thrown, we cannot accurately calculate the maximum distance. Theoretically, if the ball is thrown at an angle of 45 degrees, the distance (d) can be obtained using the formula for the range of a projectile: d = (v^2)/g, where v is the initial speed and g is the acceleration due to gravity. Substituting the value, d = (20^2)/9.81 = 40.57 meters. But this is an estimation and the value could change according to the actual circumstances when the ball is thrown.
Learn more about Projectile Motion here:
#SPJ2
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If the distance is halved and the charges of both particles are doubled, the force is 16 times as great.
Coulomb's Law
According to Coulomb's law, the electrostatic force between two charges is given by;
Where 'k' is the Coulomb's constant.
If the charges of both particles are doubled and the distance is halved, the new force will be;
So, the new force will be 16 times greater than the old force.
Learn more about Coulomb's law here:
Answer:
The new force is 16 times of the initial force.
Explanation:
The electric force between charges is given by :
If the distance is halved, d' =d/2 and charges are doubles,
New force becomes,
So, the new force is 16 times of the initial force.
b) the time taken to reach this height. (neglect the effect of air resistance).
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Technically, you can simply point out that "acceleration" MEANS
"change in velocity", so of course they have the SAME direction.
Think of it like a car. When you are slowing down to stop at a light, your velocity is still going forwards, but your acceleration is negative because it is decreasing the velocity. A negative acceleration is another way of saying that the acceleration is going in the opposite direction of the frame of reference.
If the car is speeding up, the velocity is forward, and the acceleration is in the same direction because the change of velocity is positive.
Hope this helped! :D