The two most commomly styles used to format academic papers are ?
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From middle school to college, the two most widely used formats are MLA and APA for writing essays.
-Hope this helps!
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(a) At any point between the cylinders a distance r from the axis and
(b) At any point outside the outer cylinder.
(c) Graph the magnitude of the electric field as a function of the distance r from the axis of the cable, from r = 0 to r = 2c.
(d) Find the charge per unit length on the inner surface and on the outer surface of the outer cylinder.
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Answer:
Part a)
Part b)
Part d)
As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different
On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.
Explanation:
Part a)
By Guass law we know that
Part b)
Outside the outer cylinder we will again use Guass law
Part d)
As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different
On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.
Final answer:
The electric field between the cylinders is given by E = λ / (2πε₀r). The electric field outside the outer cylinder is zero due to the absence of net charge. Graph the electric field magnitude using the equation E = λ / (2πε₀r). The inner surface charge of the outer cylinder is -λ and the outer surface charge is 0.
Explanation:
To calculate the electric field between the cylinders at a distance r from the axis, you can use Gauss's Law. Since the charging is uniform, the electric field will also be uniform. Therefore, the electric field at any point between the cylinders is given by E = λ / (2πε₀r), where ε₀ is the permittivity of free space.
To calculate the electric field at any point outside the outer cylinder, you can use the principle of superposition. The electric field due to the outer cylinder is zero because it has no net charge. The electric field due to the inner cylinder can be calculated using the same formula as before.
To graph the magnitude of the electric field as a function of the distance r from the axis, you can plot the equation E = λ / (2πε₀r) for values of r ranging from 0 to 2c.
The charge per unit length on the inner surface of the outer cylinder is -λ, while the charge per unit length on the outer surface of the outer cylinder is 0. This is because the outer cylinder has no net charge and the inner cylinder has a uniform positive charge per unit length λ.
Learn more about Electric Field here:
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Answer:
No, it would reach a height of 180m and the bird is at 200m
b. There's not enough information given to determine.
c. both vertical and horizontal.
d. entirely horizontal.
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When the ball should be thrown into the air so the velocity of the ball should be entirely horizontal.
The following information should be considered:
- The object should continue for travel having a similar velocity till the external force should be applied.
- Also, no external forces should be there in the case when it is horizontal direction except air resistance.
- The gravity force should be downwards at 9.8m/s^-2 towards the ground. At the time when the ball is at the highest point so the ball stops so, it can't be vertical.
Therefore, we can conclude that when the ball should be thrown into the air so the velocity of the ball should be entirely horizontal.
Learn more: brainly.com/question/17127206
.
An object will continue to travel with the same velocity unless an external force is applied.
There are no external forces acting in the horizontal direction (except air resistance but the is negligable) so the ball will move in the horizonontal direction with with same speed at all times.
Force of gravity is acting downwards, meaning it is constantly acelleraring at 9.8ms^-2 towards the ground. When the ball reaches its heighest point, it is where the ball has stopped moving up and starts to move down, therfore it is not moving vertically at all.
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The statement ‘According to Faraday's law, voltage cannot be changed by changing the magnetic field strength’ is false. No matter how the change is created, voltage will always be produced and it could be the magnetic field strength, moving magnet toward or away from the coil etc. This is because the voltage is directly proportional to the number of turns and the magnetic flux.
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Answer:
Explanation:
Given:
d=12.5in=0.3175m
r=d/2=0.3175/2=0.15875m
ωf=75rev/min=7.85rad/s
t=3.80s
The angular acceleration
Tangential acceleration
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When the ball reaches the highest point, its velocity will be zero. So final velocity is v=0m/s
Here, the time to reach highest point is equal to time to hit ground from highest point.
Consider upward motion, the acceleration of the ball is a=−g=−9.8m/s
2
(minus for motion opposite to gravity)
If t be the required time.
Using v=u+at,
0=25+(−9.8)t
⟹ t=2.5s
Thus the ball hits the ground after 2.5 seconds after reaching its highest point.