Answer:
x has no real solution
Step-by-step explanation:
Our equation is qudratic equation so the method we will follow to solve it is using the dicriminant :
B. Pyramid
C. Cone
D. Polygon
The Prism and Pyramid is a typical example of polyhedron. That is optionA and B.
A polyhedron is any solid that has a three dimensional shape with all its sides flat. It is made up of different polygons that join together.
These polyhedron are made up of three parts:
Examples of polyhedron are the Prism and Pyramid. The prisms have flat faces and is made up of rectangles while the pyramids is made up of triangles and different polygons.
Therefore, the Prism and Pyramid is a typical example of polyhedron.
Learn more about polyhedron here:
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I really don't know how to calculate this question.
(3 tan 45°)(4 sin 60°)-(2 cos 30°)(3 sin 30°)
Answer:
, which is equal to .
Step-by-step explanation:
An angle of corresponds to an isosceles right triangle: the length of the two legs (adjacent and opposite) would be equal. Accordingly:
.
Let denote the measure of an angle. Double-angle identity for sine:
.
By this identity:
.
( in this instance.)
Hence:
.
. Therefore, .
Answer:
2/3x + 1
Step-by-step explanation:
The y-intercept is 1. you can see that when x increases three, y increases 2.
Answer:
c = 149 + 0.02p
Step-by-step explanation:
Answer:
The probability that the O-ring came from Galshus and Sons given that it is defective is 0.359.
Step-by-step explanation:
Probability of getting O-ring from Little Rock Plastics = 0.29
Probability of getting O-ring from Galshus and Sons = 0.71
Probability of getting Defective Rings from Little Rock Plastics = 0.04
Probability of getting Defective Rings from Galshus and Sons = 0.10
Denoting Little Rock Plastics as LRP, Galshus and Sons as GS and Defective as D, we can write:
P(LRP) = 0.29
P(GS) = 0.71
P(D ∩ LRP) = 0.04
P(D ∩ GS) = 0.10
We are given that an O-ring is found to be defective and we need to find the probability that it came from Galshus and Sons so we will use the conditional probability formula for calculating the probability that the O-ring came from Galshus and Sons given that it is defective.
P(GS|D) = P(D ∩ GS)/P(D)
We need to compute P(D) first. So,
P(D) = P(D|GS) + P(D|LRP)
= P(D∩GS)/P(GS) + P(D∩LRP)/P(LRP)
= 0.10/ 0.71 + 0.04/0.29
= 0.1408 + 0.1379
P(D) = 0.2787
P(GS|D) = P(D ∩ GS)/P(D)
= 0.10/0.2787
= 0.3587
P(GS|D) = 0.359
Using Bayes' theorem, the probability that a defective O-ring came from Galshus and Sons is approximately 0.802 or 80.2%
To find the answer to your question, we need to use Bayes' theorem. This theorem refers to the probability of an event, based on prior knowledge of conditions that might be related to the event. First, let us identify the following:
Probability of choosing an O-ring from Little Rock Plastics (L), P(L) = 0.29
Probability of choosing an O-ring from Galshus and Sons (G), P(G) = 1 - P(L) = 0.71
Probability that an O-ring from Little Rock is defective, P(D|L) = 0.04
Probability that an O-ring from Galshus and Sons is defective, P(D|G) = 0.10
By Bayes' theorem, the probability that a defective O-ring came from Galshus and Sons is given by: P(G|D) = [P(G) * P(D|G)] / [P(L) * P(D|L) + P(G) * P(D|G)]
Upon substitution, P(G|D) = [0.71 * 0.10] / [0.29 * 0.04 + 0.71 * 0.10]. This equates to approximately 0.802, or 80.2%, meaning there is a 80.2% chance that the defective O-ring came from Galshus and Sons.
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