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Answer:
n = 12.
Step-by-step explanation:
Given:
5/6n = 10
Solve by isolating the variable. Divide both sides by 5/6. (Multiply by the reciprocal)
5/6n · 6/5 = 10 · 6/5
n = 10 · 6/5
n = 12.
Answer:
6n = 10 ×5
6n = 50
n = 50/6
n = 8.3
Answer: The answer is 3700
Answer:3.72
Step-by-step explanation:
Answer:
19
Step-by-step explanation:
1st day: x
2nd day: x+3
3rd day: x+4
Equation: x+(x+3)+(x+4)=64
3x+7=64
3x=57
x=19
I hope you found this answer helpful!!!!!!(sorry if instructions aren't clear)
Equation B: 3x + 2z = 1
Which of the following is a possible step used in eliminating the z-term?
Multiply equation A by −2.
Multiply equation B by 2.
Multiply equation A by 3.
Multiply equation B by 3.
Answer:Multiply equation A by -2 is correct everyone
Step-by-step explanation:
I just took the test and checked;)
Answer:
slope = -
Step-by-step explanation:
calculate the slope m using the slope formula
m =
let (x₁, y₁ ) = (6, 0 ) and (x₂, y₂ ) = (- 3, 2 )
substitute these values into the formula for m
m = = = -
I believe the answer is x ≤ -60.
Answer:
90 mi/h
Step-by-step explanation:
Calculate speed, distance, or time using the formula d = st, distance equals speed times time. The Speed Distance Time Calculator can solve for the unknown sdt value given two known values.
Time can be entered or solved for in units of seconds (s), minutes (min), hours (hr), or hours and minutes and seconds (hh:mm:ss).
To solve for distance use the formula for distance d = st, or distance equals speed times time.
distance = speed x time
Rate and speed are similar since they both represent some distance per unit time like miles per hour or kilometers per hour. If rate r is the same as speed s, r = s = d/t. You can use the equivalent formula d = rt which means distance equals rate times time.
distance = rate x time
To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time.
speed = distance/time
To solve for time use the formula for time, t = d/s which means time equals distance divided by speed.
time = distance/speed
Plane speed in still air: 120mph
Wind speed: 30pmh
Speed of plane to Bismarck: 90mph
Speed of plane to Fargo: 150mph