Many fundraisers ask for donations using e-mail and text messages. The paper "Now or Never! The Effect of Deadlines on Charitable Giving: Evidence From Two Natural Field Experiments" ( Journal of Behavioral and Experimental Economics [2016]: 1-10) describes an experiment to investigate whether the proportion of people who make a donation when asked for a donation by e-mail is different from the proportion of people who make a donation when asked for a donation in a text message. In this experiment, 1.32% of those who received and opened an e-mail request for a donation and 7.77% of those who received a text message asking for a donation actually made a donation. Assume that the people who received these requests were randomly assigned to one of the two groups (e-mail or text message) and suppose that the given percentages are based on sample sizes of 2000 (the actual sample sizes in the experiment were much larger). a. The study described is an experiment with two treatments. What are the two treatments?
b. Use a 90% confidence interval to estimate the difference in the proportions who donate for the two different treatments
c. Is there convincing evidence that the proportion who make a donation is not the same for the two different methods? Carry out a hypothesis test using a significance level of 0.05.
d. Is there convincing evidence that the proportion who make a donation after receiving an email is smaller than the proportion who make a donation after receiving a text message? Carry out a hypothesis test using a significance level of 0.10.

Answers

Answer 1
Answer:

Answer:

IT SAYS YOU IN COLLEGE SOOO YOU SHOULD BE ABLE TO ANSWER IT YOUR SELF

Step-by-step explanation:


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A sample of 16 items from population 1 has a sample variance 5.8 and a sample of 21 items from population 2 has a sample variance 2.4. Test the following hypotheses at the .05 level of significance. H0: Population 1 Variance < Population 2 Variance Ha: Population 1 Variance > Population 2 Variance a. What is the p-value

A newspaper carrier has ​$7.10 in change. He has nine more quarters than dimes but three times as many nickels as quarters. How many coins of each type does he​ have?

Answers

Let q represent the number of quarters he has. Then q-9 is the number of dimes, and 3q is the number of nickels. His total change is ...

0.25q + 0.10(q-9) + 0.05(3q) = 7.10

0.50q - 0.90 = 7.10

q = (7.10 +0.90)/0.50 = 16

The carrier has 16 quarters, 7 dimes, and 48 nickels.

Find the discounted price:
$40 jacket; 33% discount

Answers

$26.8

Multiply 40 by .67

Answer:

$26.8

Step-by-step explanation:

To find the discount, you turn the percentage of the discount into a decimal (.33) then multiply it by the original price (40)

$40 x .33 = 13.2

You then subtract the total to the original price of the item (40)

$40 - 13.2 = 26.8

So the discount price of the jacket would be $26.8

Hope this helps!!

-Jerc

You have 14 gallons of lemonade to sell. You use cone-shaped cups that are 9 centimeters in diameter and 11 centimeters tall. Eachcustomer uses one paper cup. How many paper cups will you need if you sell all of the lemonade? (1 gal = 3785 cm)

Answers

Answer:

You need to sell approximately 119 paper cups to sell all of the lemonade.

Step-by-step explanation:

You need to lay communications cable around the perimeter of three offices, each 8' by 10'. How much cable do you need?

Answers

Answer:

108 units

Step-by-step explanation:

We are given that

Length of each  office,l=10 units

Breadth of each office=b=8 units

Total number of office=3

We know that

Perimeter of rectangle=2(l+b)

Using the formula

Length of cable for 1 office=2(10+8)=36units

Length of cable required for 3 offices=36* 3=108units

Hence, the required length of cable=108 units

Give me the answer now​

Answers

Answer:

what is the Question

Step-by-step explanation:

Prove that the diagonals of a rectangle bisect each other.Plan: Since midpoints will be involved, use multiples of __ to name the coordinates for B, C, and D.




2


4


1


3

Answers

Answer:

2

Step-by-step explanation:

example A(2a,0),B(2b,0)

C(2b,2c),D(2a,2c)

mid point of AC=((2a+2b)/2,(0+2c)/2)=(a+b,c)

mid point of BD=((2b+2a)/2,(0+2c)/2)=(a+b,c)

∴midpoint of diagonals same or diagonals bisect each other.