During a sale, a shop allows 20% discount off the marked price of clothing. What will a customer pay for a dress with a marked price of $30? * 1 point

Answers

Answer 1
Answer:

Answer:

$24

Step-by-step explanation:

Let the full price of $30 be 100%.

If the discount allowed is 20%, then the percentage of the original price that a customer will pay is:

P=100\%-20\%\nP=80\%

80% of a marked price of $30 is:

80\%*\$30\n\$24

A customer will pay $24.

Answer 2
Answer: They will pay 24 dollars

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Nikki is participating in a charity walk thisweekend. She walks at a pace of 4.2 miles
per hour. How long will it take her to walk
35.7 miles?

Answers

Answer:

8.5 hours

Step-by-step explanation:

We know that it takes Nikki 1 hour to walk 4.2 miles.

We need to figure out how long it will take her to walk 35.7 miles.

This is our expression; 35.7 ÷ 4.2.

Let's go ahead and divide these two numbers.

(35.7 ÷ 4.2) = 8.5

So It will take Nikki 8.5 hours to walk 35.7 miles.

Feel free to give brainliest.

Have an excellent day!

$6300 is invested , part of it at 12%, and part at 6%.  For a certain year, the total yield is 564.00.  How much was invested at each rate?

Answers

x - first part of the investment (12% rate)
y - second part of the investment (6% rate)

Total investment: x + y = 6300
Total yield: 564 = x*0,12 + y*0,06

Based on that we can calculate x and y:
\left \{ {y=6300-x} \atop {0,12x+0,06(6300-x)=564}} \right.

\left \{ {y=6300-x} \atop {0,12x+378-0,06x=564}} \right.

\left \{ {y=6300-x} \atop {0,06x=186}} \right.

\left \{ {y=6300-x} \atop {x=3100}} \right.

\left \{ {y=3200} \atop {x=3100}} \right.

Answer: $3100 was invested at 12% and $3200 at 6%.

If you have any questions, please let me know!

Mike wanted to purchase a bike for $285.00 andrealized the bike was on sale for 30% off. How much
would Mike pay for the bike, before taxes, once the
discount was applied?
A. $85.50
B. $199.50
C. $315.00
D. $370.50

Answers

Answer:

B

Step-by-step explanation:

285 × .30 = 85.50

285 - 85.50 = 199.50

Is LNM =(~) OQP? If so, name the postulate that applies.

Answers

Answer:

The postulate that applied if $$\triangle L N M \cong \triangle O Q P$$ is an option (b) Congruent -ASA.

Step-by-step explanation:

What is Congruent -ASA?

By the Congruent -ASA rule, two angles in one triangle are congruent with two angles in a second triangle, and if the sides included in both triangles are also congruent, then the triangles are congruent.

Determine the postulate if  $$\triangle L N M \cong \triangle O Q P$$:

Given:

&\overline{\mathrm{LM}} \cong \overline{\mathrm{OP}} \n

&\overline{\mathrm{MN}} \cong \overline{\mathrm{PQ}} \n

&\angle \mathrm{M} \cong \angle \mathrm{P}

Here, the answer is obvious from the question,

\angle \mathrm{M} is LM and MN's Angle.

$\angle P$ is PQ and PO's Angle.

Hence, it is ASA.

So, if the angle $$\triangle L N M \cong \triangle O Q P$$, then the postulate that is applied is Congruent -ASA.

To learn more about Congruent -ASA here:

brainly.com/question/10349343

Yes; LNM ~ OQP because of the SAS~ postulate

If a pair of parallel lines are rotated, which is true?A) The lines remain parallel only if rotated 180°.
B) The lines remain parallel only if rotated 360°.
C) Rotated parallel lines always remain parallel lines.
D) Rotating parallel lines result in perpendicular lines.

Answers

Answer:

C) Rotated parallel lines always remain parallel lines.

Step-by-step explanation:Rotated parallel lines remain parallel lines.

Rotation is a rigid transformation, so the lines remain parallel.

Answer:

c

Step-by-step explanation:

rotated parallel lines remain parallel lines

Determine whether the relation is a function. {(5, 0), (8, 1), (1, 3), (5, 2), (3, 8)}

Answers

No. If an x value repeats it is not a function.