Lots of equations that equal 420? Anybody know some? 

Answers

Answer 1
Answer: If we do it algebraically, we get

x + y = 420

This is the simplest equation. You see now this is a linear pair in two variables. Thus, there will be infinitely many solutions.

E.g - 419 + 1 = 420

42 * 10 = 420
21 * 20 = 420

etc,....
Answer 2
Answer: 42 times 10 
210 times 2
210 + 210
70 times 6
60 tmes 7
140 times 3

 
and etc

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How do you find the ratio of a fraction

Answers

A ratio is the relationship between two numbers.

Probably the easiest way to write a ratio is in the form of a fraction. 

A fraction IS a ratio. 

It means (the top number) divided by (the bottom number), and
that's the ratio between them.

How to write 6 less than one-fourth of C?

Answers

less than = subtracted from
one fourth of c = 1/4 times c

(1)/(4) c-6

(c)/(4) -6
6 less than one-fourth of c is 1/4c-6

Jack is playing a game where he flips a coin and rolls a number cube labeled 1 through 6. He listed the possible outcomes in the sample space shown below.{(H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5)}

Which two elements did he leave out by mistake?

(H, 1) and (T, 6)
(H, 6) and (T, 1)
(H, 2) and (T, 6)
(T, 1) and (T, 6)

Answers

Answer:  The correct option is (A) (H, 1) and (T, 6).

Step-by-step explanation: Given that Jack is playing a game where he flips a coin and rolls a number cube labeled 1 through 6.

Jack listed the possible outcomes in the sample space 'S'' as follows:

S' = {(H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5)}

We are given to select the correct option that contains the two elements Jack left out by mistake.

The sample space for the event of flipping a coin is {H, T}

and

the sample space for the event of rolling a number cube labeled 1 through 6 is {1, 2, 3, 4, 5, 6}.

Let, 'S' represents the actual sample space for the event.

Then, we get

S = {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6)}.

Comparing S with S', the two missing elements were (H, 1) and (T, 6).

Thus, the correct option is (A).

The answer is (H, 1) and (T, 6)

Using the formula A=l•w solve the following word problem. You have enough wallpaper to cover 240 square feet. If your walls are 8 feet high, what wall length can you paper? a. Wall length of 40 feet
b. Wall length of 30 feet
c. Wall length of 3 feet
d. Wall length of 16 feet

Answers

Hi there! The answer is B.

You have enough wallpaper to cover 240 square feet. If your walls are 8 feet high, what wall length can you paper?

First write down our data:
A = 240 square feet
l = 8 feet

Now we can fill in the formula
240 = 8 × w

Switch sides.
8 × w = 240

Divide both sides by 8.
w = 240 / 8 = 30

Therefore the answer is B.
Wall length of 30 feet

Final answer:

Using the formula A=l•w to solve the wallpaper problem, where the area (A) is 240 square feet and the width (w) is the height of the walls (8 feet), we find that the wall length (length) that you can paper is 30 feet.

Explanation:

The subject of the word problem is finding the wall length you can cover with a given amount of wallpaper. In this case, the area of the wallpaper is 240 square feet, and the height of the walls is 8 feet.

The formula for the area of a rectangle is A=l•w, where A stands for area, l stands for length, and w stands for width. In this case, the 'width' is the height of the walls, which is 8 feet.

To find the length of the wall, we can rearrange the formula to l=A/w and substitute the given values. That means l=240/8, which gives us a wall length of 30 feet.

Therefore, the answer is b. Wall length of 30 feet.

Learn more about Area Calculation here:

brainly.com/question/34380164

#SPJ2

6. The equation of line A is 3x + 6y - 1 = 0. Give the equation of a line that passes through thepoint (5,1) that is

/1 a. Perpendicular to line A

Answer:

/1 b. Parallel to line A

Answer:

Answers

Step 1: Convert to slope-intercept form to find the slope of the line.

This isn't necessary if you know all the shortcuts, it just makes your life a bit easier.

3x+6y-1=0\n6y=-3x+1\ny=-(3)/(6)x+(1)/(6)\n-(1)/(2)x+(1)/(6)

Now we want to find the equations for our new lines. It's easiest to do this in slope-intercept form, so let's start finding the slope and y-intercept.

So for the perpendicular line, the slope is going to flip and change signs, this is aka its opposite reciprocal.
And for the parallel line, it'll stay the same.

-(1)/(2) ⇒ (2)/(1)=2
-(1)/(2) ⇒ -(1)/(2)

As for the y-intercept, just apply that slope until you get a point where x=0.

(5, 1) with a rise of 2 and a run of 1...let's work backwards to (0, b)
(5, 1), (4, -1), (3, -3), (2, -5), (1, -7), (0, -9).

(5, 1) with a rise of -1 and a run of 2...let's work backwards to (0, b)
(5, 1), (3, 0), (1, -1)...gonna have to take half a step here...(0, -1.5).

Now let's construct our equations in slope-intercept form.

y = 2x-9\ny=-(1)/(2)x-(3)/(2)

And now it's time to convert to general form!

Make sure we have common denominators...check.

Multiply by the denominator...

y=2x-9\n2y=1x-3

...check.

Aaaand bring everything over!

\boxed{-2x+y-9=0}\n\boxed{-x+2y-3=0}

do sets always have an intersection that is not the empty set? provide an example to support your conclusion?

Answers

i don't know sorry but you can ask some one else error 404