. A coin is tossed three times, and the sequence of heads and tails is recorded.(a) Determine the sample space, Ω.(b) List the elements that make up the following events: i.A= exactly two tails, ii.B= at least twotails, iii.C= the last two tosses are heads(c) List the elements of the following events: i.A, ii.A∪B, iii.A∩B, iv.A∩C

Answers

Answer 1
Answer:

Answer:

See explanation below

Step-by-step explanation:

Here a coin was tossed three times.

Let H = head &  T = tail

Find the following:

a) The sample space:

Since a coin is tossed thrice, all possible outcome would be:

S = { HHH, HHT, HTH, HTT, TTT, TTH, THH, THT}

b) i) A = Exactly 2 tails: Here exactly 2 tails were recorded.

A = {HTT, TTH, THT}

ii) B = at least two tails: Here 2 or more tails were recorded.

B = {HTT, TTT, TTH, THT}

iii) C = the last two tosses are heads:

C = { HHH, THH}

c) List the elements of the following events:

i) A. This means all outcomes in A

= {HTT, TTH, THT}

ii) A∪B. A union B, means all possible outcomes present in A or B or in both

= {HTT, TTH, THT, TTT}

iii) A∩B. This means all possible outcomes of A that are present in B.

= {HTT, TTH, THT}

iv) A∩C. All outcomes A that are present in B

= {∅}

Answer 2
Answer:

The sample space of tossing a coin three times consists of eight possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT. Events A, B, and C can be determined by listing the appropriate outcomes. The intersection and union of events A and B can also be determined.

(a) The sample space, Ω, of tossing a coin three times can be determined by listing all the possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT.

(b) i. A = {HHT, HTH, THH}

ii. B = {TTT, TTH, THT, HTT, HHT, HTH, THH}

iii. C = {HTH, TTH}

(c) i. A = {HHT, HTH, THH}

ii. A∪B = {HHT, HTH, THH, TTT, TTH, THT, HTT, HHT}

iii. A∩B = {HHT, HTH, THH}

iv. A∩C = {HHT, HTH}

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A researcher examines 27 sedimentary samples for bromide concentration. The mean bromide concentration for the sample data is 0.383 cc/cubic meter with a standard deviation of 0.0209. Determine the 90% confidence interval for the population mean bromide concentration. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Answers

Answer:

Critical value: z = 1.645

The 90% confidence interval for the population mean bromide concentration is (0.376, 0.39).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = (1-0.9)/(2) = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This value of z is the critical value

Now, find M as such

M = z*(\sigma)/(√(n))

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*(0.0209)/(√(27)) = 0.0066

The lower end of the interval is the mean subtracted by M. So it is 0.383 - 0.0066 = 0.376 cc/cubic meter

The upper end of the interval is the mean added to M. So it is 0.383 + 0.0066 = 0.39 cc/cubic meter

The 90% confidence interval for the population mean bromide concentration is (0.376, 0.39).

What is the measure
of angle x?

Answers

Answer:

A.) 48°

Step-by-step explanation:

There is a right angle and an angle of 42°

Therefore

x=180-90-42. (sum of int angles of triangle)

x=48°

Answer:

(A) 48

Step-by-step explanation:

Triangles have 180°, so all you have to do is subtract the numbers you already know from 180.

180-42 = 138

The square on the left corner means that degree is a right angle. Right angles are always 90°.

138-90 = 48degrees

If I helped at all please give brainliest! :)

This pattern repeats every 5 terms. The pattern is rectangle, pentagon, square, hexagon, pentagon. What is the 19th term of this pattern? Answers Square
Pentagon
Hexagon
Rectangle

Answers

Since the pattern repeats every 5 terms, we can find the remainder when 19 is divided by 5 to determine which term in the pattern the 19th term corresponds to.

19 ÷ 5 = 3 with a remainder of 4

Since there are 5 terms in the pattern, the 19th term is equivalent to the 4th term in the pattern. Therefore, the 19th term is a square.

Use​ Gauss's approach to find the following sum​ (do not use​ formulas):5+11+17+23...+83

Answers

Denote the sum by S. So

S = 5 + 11 + 17 + 23 + ... + 83

There's a constant difference of 6 between consecutive terms in S, so the 3 terms before 83 are 77, 71, and 65. So

S = 5 + 11 + 17 + 23 + ... + 65 + 71 + 77 + 83

Gauss's approach involves inverting the sum:

S = 83 + 77 + 71 + 65 + ... + 23 + 17 + 11 + 5

If we add terms in the same position in the sums, we get

2S = (5 + 83) + (11 + 77) + ... + (77 + 11) + (83 + 5)

and we notice that each grouped term on the right gives a total of 88. So the right side consists of several copies n of 88, which means

2S = 88n

and dividing both sides by 2 gives

S = 44n

Now it's a matter of determining how many copies get added. The terms in the sum form an arithmetic progression that follows the pattern

11 = 5 + 6

17 = 5 + 2*6

23 = 5 + 3*6

and so on, up to

83 = 5 + 13*6

so n = 13, which means the sum is S = 44*13 = 572.

Final answer:

To find the sum of the given arithmetic series, we can use Gauss's approach by finding the number of terms and then calculating the sum using the formula for the sum of an arithmetic series.

Explanation:

To find the sum of the given series, we can use Gauss's approach. The series is an arithmetic progression with a common difference of 6. We can find the number of terms in the series using the formula for the nth term of an arithmetic sequence and then use the formula for the sum of an arithmetic series to find the sum.

  1. Find the number of terms (n):
    1. The first term (a) is 5, and the common difference (d) is 6.
    2. Find the last term (l) using the formula: l = a + (n - 1)d
    3. Substitute the values and solve for n: 83 = 5 + (n - 1)6
    4. Simplify and solve for n: n = 15
  2. Find the sum (S):
    1. The formula for the sum of an arithmetic series is: S = (n/2)(a + l)
    2. Substitute the values and solve for S: S = (15/2)(5 + 83)
    3. Calculate the sum: S = 15(44)
    4. Simplify the sum: S = 660

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Easy algebra! Just need help with this one

Answers

The answer is B (9,6) (12,8)

The environmental science club is printing T-shirts for its 15 members. The printing company charges a certain amount for each shirt plus a setup fee of $20. If the T-shirt order costs a total of $162.50, how much does the company charge for each shirt?

Answers

Final answer:

After subtracting the setup fee from the total cost, the remaining amount ($142.50) is divided by the number of t-shirts (15) to find the cost of each shirt, which is $9.5.

Explanation:

The total cost for the T-shirt order is $162.50 and this includes a $20 setup fee. If you subtract this setup fee from the total cost, you will be left with the total cost of the actual T-shirts.

This gives us: $162.50 - $20 = $142.50.

The total cost of the T-shirts is $142.50, and this is for the 15 members of the club. To find out a cost of each shirt, you would divide this amount by the number of shirts, which is 15:

$142.50 / 15 = $9.5.

So, the company charges $9.5 for each shirt.

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Answer:

x=9.5

Step-by-step explanation:

Let  be the cost of each shirt. From the information provided in the problem, we can setup the following equation:

Solving for  will give us the answer:

GG

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