b. 1067
c. 1.13
d. 63
Answer: the correct answer is option(d).
Explanation:
Energy required ,Q= ?
Mass of water , m = 17 grams
Temperature difference or = 15 °C
Specific heat value of water = 4.186 J/g °C
From the given value the , nearest value to to our calculated answer is 1067 J that option (b).
Hence, the correct answer is option (d).
Energy is absorbed making it feel colder.
The reaction container always feels hot.
The reactants have less heat energy than the products.
More heat is given off than is put into the reaction.
Answer:
-The reactants have less heat energy than the products.
Explanation;
-An endothermic reaction is a reaction in which heat energy is absorbed from the surroundings. In such a reaction the energy of the reactants is less than the energy of the products and therefore the enthalpy change is positive, greater than zero.
The answer is Energy is absorbed making it feel colder. Endothermic reactions absorb heat from their environment (hence lowering the temperature of the nearby environment), unlike ectothermic reactions that release energy to their environment . The enthalpy of products in an endothermic reaction is higher than that of the reactant hence the change in enthalpy is positive.
a. Reduction
b. Decomposition
Oxidation
d. Acid-Base Netralization
Answer:
The correct answer is reduction.
Explanation:
Nitrogen gas reacts with hydrogen gas and get reduced to form ammonia. In this reaction.This is important reaction of atmospheric nitrogen fixation.The reaction is carried out by many nitrogen fixing bacteria such as Azotobacter,Clostridium etc.
N2+3H2+6e- = 2NH3
The reaction N2 + 6e → 2N-3 represents reduction, where nitrogen gains electrons to form N-3 ions.
The reaction N2 + 6e → 2N-3 represents reduction. In this reaction, nitrogen (N2) gains electrons (e) to form N-3 ions. Reduction is a process in which an atom or ion gains electrons, resulting in a decrease in its oxidation state.
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4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ
The value of ΔH will be 249.75 KJ.
To obtain the reaction :
PCl5(g) → PCl3(g) + Cl2(g)
We have to add the given reactions and then divide it by 4.
(i) adding the reactions
P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = -2439 kJ
4PCl5(g) → P4(s) + 10Cl 2(g) ΔH = 3438 kJ
we get:
4PCl5(g) → 4PCl3(g) + 4Cl2(g), ΔH = 3438 - 2439
(ii) dviding by 4
PCl5(g) → PCl3(g) + Cl2(g) , ΔH = (3438 - 2439)/4
ΔH = 249.75 kJ is the required enthapy.
Learn more about enthalpy:
Answer:
The value of for the desired reaction will be 249.75 KJ.
Explanation:
The desired reaction is shown below
The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.
Net Enthalpy change for the desired reaction