What are the sides of the DNA ladder made of?
The sides of the DNA ladder are made of alternating deoxyribose sugar molecules and phosphate groups.
The DNA molecule has a double helix structure, resembling a twisted ladder. The sides, or rails, of this ladder are composed of two long chains of nucleotides running in opposite directions. Each nucleotide consists of three components: a deoxyribose sugar molecule, a phosphate group, and a nitrogenous base (adenine, thymine, cytosine, or guanine). The deoxyribose sugar molecules and phosphate groups alternate to form the backbone of the DNA strand. The phosphate groups link the sugar molecules together through covalent bonds, creating a strong and stable structure.
The nitrogenous bases, which include adenine (A), thymine (T), cytosine (C), and guanine (G), project inward from the sugar-phosphate backbone and form complementary base pairs (A with T and C with G) between the two DNA strands. These base pairs are held together by hydrogen bonds, which provide the specificity and complementarity necessary for DNA replication and information storage. This elegant molecular architecture allows DNA to store and transmit genetic information accurately.
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Answer:
Explanation:
Hey,
so here the student is saying that the given mass is of one atom. But when we usually talk about amu it is the unified atomic mass so mass of all the atoms present.
So that's why he is wrong.
Also the definitions states,
The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit (amu, also known as daltons, D). The atomic mass is a weighted average of all of the isotopes of that element, in which the mass of each isotope is multiplied by the abundance of that particular isotope.
Answer:
See below.
Explanation:
121.76 amu is the Relative Atomic Mass of Antimony (the average mass of the different isotopes). . The element exists as a mixture of isotopes , the main one being SB121 which has a mass of 121.
The amount of aluminum deposited when a current of 10A is passed through a solution of aluminum salt for 1930s is 5.4 g.
An electrochemical cell converts chemical energy into electrical energy. Metals with higher negative electrode potential undergo oxidation and its ionization produces electron flow through the solution.
The weight of the metal that deposited by reduction is related to the mass of metal, current passed and time as follows:
w = z It
where z = E/96500 F
Equivalent mass of Al, E = 27 g
t = 1930 s
current I = 10 A.
Now, the weight of aluminum metal deposited is calculated as follows:
w = 1930 s × 10 A × 27/96500 = 5.4 g.
Therefore, the weight of Al deposited on the electrode is 5.4 g.
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Answer:
AL*3+ + 3e- =AL.
(10A×1930)÷96500=0.2mole e-
0.2÷3×27=1.8g(AL)
There are way more than 5 but I will list the ones I know:
Reaction with acid
Reaction with water
Combustion/Flammability
Combination
Redox
Isomerization