Answer:
closed questions are questions with fixed answer options
A. Closed questions allow the respondent to go in-depth with their answers.
B. It is possible to automate the collection of results for closed questions.
C. Closed questions allow for new solutions to be introduced.
D. It is easy to quantify and compare the results of surveys with closed questions.
Answer:
$21 dollars
Step-by-step explanation:
b. What is the probability that the gun detects speeding and the driver was not speeding?
c. Suppose the police stop a driver because the gun detects speeding. What is the probability that the driver was actually driving below the speed limit?
Answer:
a) P(A∩B) = 0.21
b) P(A∩B') = 0.0072
c) P(B'|A)=0.0072/0.2172=0.0331
Step-by-step explanation:
A = the gun will detect a speeder
B = driver is actually speeding
P(A|B) = 0.75
P(A|B')=0.01
P(B') = 0.72
a) by definition
P(A∩B)=P(A|B)*P(B)=0.75*(1-0.72)=0.21
b) by definition
P(A∩B')=P(A|B')*P(B')=0.01*(0.72)=0.0072
c)
by bayes theorem
P(B'|A)=P(A|B')*P(B')/P(A)
by total probability theorem
P(A)=P(A∩B)+P(A∩B')=0.21+0.0072=0.2172
so
P(B'|A)=0.0072/0.2172=0.0331
The probabilities asked in the question are calculated using basic principles of probability: a) the probability that the radar gun detects speeding and the driver was speeding is 21%, b) the probability that the radar gun detects speeding, and the driver was not speeding is 0.72%, c) given that a driver is stopped because the radar gun detected speeding, the probability that they were actually driving within the speed limit is 3.3%.
The probability of a speed detection can be divided into two different categories – the probability of an accurate detection (where the driver is actually speeding), and a false detection (where the driver is not speeding).
a. The probability that the gun detects speeding and the driver was speeding is calculated by the accuracy of the gun, which is 75%, multiplied by the percentage of drivers that are actually speeding. Given that 28% of the drivers exceed the speed limit (100% - 72% safe drivers), the probability is 0.75*0.28 = 0.21 or 21%.
b. The probability that the gun detects a speeder when the driver is not speeding is calculated by multiplying the probability the gun makes an error (1%) and the chance that the driver is driving within the speed limit (72%). So, 0.01*0.72 = 0.0072 or 0.72%.
c. If the police stop a driver because the gun detects speeding, the probability that the driver was actually driving safely is calculated by taking the probability that the gun gives a false speed reading (0.72%) and dividing it by the total probability that the gun detects a speeding vehicle (accurate detection + false detection = 21% + 0.72% = 21.72%). So, 0.72 / 21.72 = 0.033 or 3.3%.
#SPJ3
Answer:
99
Step-by-step explanation:
102-2=100
100-1=99
or
102-3=99
Answer:
the probability that the first to arrive has to wait longer than 10 mins is 35/36.
Step-by-step explanation:
First you need to denote by X and Y the time past 12 noon that the man and woman arrive.
Then you have to compute P(X+10<Y)+P(Y+10<X), which by symmetry equals 2P(X+10<Y).
So basically you have to compute P(X+10<Y).
check the attachment for the rest of the step by step.
Answer should be 25/72
But since we want 2× of the above probability 2× 25/72 = 25/36finalanswer.
-1
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1
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Answer:
A. -1
Step-by-step explanation:
hope this helps
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