Answer: True
When two lines are crossed by another line (which is called the Transversal), the angles in matching corners are called corresponding angles. When the two lines are parallel Corresponding Angles are equal.
Answer: U, W, Z and Y
Step-by-step explanation:
4 points are not coplanar if there does not exist any plane that contains the 4 points.
So, a plane is formed by a line and one point outside of it.
Then, we want to select the last point in such a way that it lies outside of the plane generated by the first 3 points selected.
For example:
If first we select Point U and Point W, we will have a line, as shown in the image.
Now we can select the Point Z, that is outside the line, and now we have the plane M that you can see in the image.
Now we need to select a point that is not in the plane, the only two options are Point X and Point Y, we can select any of those two, let's take the Point Y.
So, here we have that:
Points U, W, Z and Y are not coplanar.
The graph of the equation is a single point, representing one solution to the equation.
The point (1, 1) is on the graph of the equation.
4x−y=−3 has the same graph.
Since the point (0, −3) is a solution to the equation, it is on the graph of the equation.
The graph of the equation is the set of all points that are solutions to the equation.
The correct answer for this question would be:
"The graph of the equation is the set of all points that are solutions to the equation."
"The point (1, 1) is on the graph of the equation."
And "The point (0, -3) is on the graph of the equation."
- I just took the test.
Answer:
8 hours and 30 minutes ight.
Step-by-step explanation:
Some math and adding and stuff I did it in my head.
Answer:
Step-by-step explanation:
8 hours 30 minutes
Answer:
Step-by-step explanation:
A). y = |2x - 3| + 1
Domain of function is defined by the x-values (Input values) and Range by the y-values(Output values).
From the graph,
Domain : (-∞, ∞)
Range : [1, ∞)
B). Table of the input-output values of the function,
y = x² - 2x + 1
x -2 -1 0 1 2
y 9 4 1 0 1
By graphing the function as attached,
Domain of the function : (-∞, ∞)
Range of the function : [0, ∞)
C). x² + y² = 3²
Domain of the function : [-3, 3]
Range of the function : [-3, 3]
D). x = 5
Domain of the line : [5, 5]
Range of the line : (-∞, ∞)