Given a polynomial f(x), if (x - 2) is a factor, what else must be true?f(2) = 0

f(-2) = 0

f(0) = 2

f(0) = -2

Answers

Answer 1

Answer: If a number is a root of a polynomial, then we substitute the number to x of the polynomial, the answer or y is equal to zero. Hence, in this situation, if (x - 2) is a factor, the root is equal to 2. This means then that upon substituting 2 to the function, y is equal to zero. Answer then is A. f(2) = 0

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Need to see how you divide 247÷100

Answers

It's very easy to divide 100 into a number because although it might be a decimal, there is no really difficult dividing going on.

100 goes into 247
2 times and then there is .47 remaining. This means 100 cannot be divided equally into this number but it will be a decimal.

Your answer would look like this:

2.47

Solve. 10/3x + 4/3 = 7+x/2x
A) X = 1/3
B) X = 17/5x
C) X = 1/5
D) X = 1/6

Answers

well multiply both sides by 6x and you get 20+ 8x = 21 + 3x. so x=1/5 so (C)

Example 1:For the function f(x) = x + 4, what is the ordered pair for the point on the graph when x = 3p?

Example 2:
If g(x) = 3(x − 2), find the value of x if g(x) = 6

The question is what is F(1) , what dose it equal?
@taskmasters @ShootingStar28 @ayah1

Answers

Simply substitute x by its value:

1)
f(x) = x + 4 ; x = 3p f(x) = x + 4 ;
f(3p) = 3p + 4 f(1) = 1 + 4
f(1) = 5
x = 3p (1,5)
y = 3p + 4

2) g(x) = 3(x-2) g(x) = 3(x-2)
g(x) = 6 g(1) = 3(1-2)
g(1) = 3 - 6
6 = 3x - 6 g(1) = -3
6+6 = 3x (1,-3)
12 = 3x
x = 4
g(4) = 3(4-2)
g(4) = 12 - 6
g(4) = 6

x = 4
y = 6

It 3:00 here, and Australia is 13 hours ahead of us what time is it in Australia?

Answers

if it's 3 a.m
in Australia it is 4 p.m

3:00am or 15:00 in Australia I think

The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?

Answers

This one is a bit confusing but I'll try to answer. Since the sum is given and one of the addend is given, we need to perform subtraction to get the other addend.

8d⁵ - 3c³d² + 5c²d³ - 4cd⁴ + 9 ⇒ SUM
- 2d⁵ - c³d² + 8cd⁴ + 1 ⇒ 1ST ADDEND
6d⁵ - 2c³d² + 5c²d³ -12cd⁴ - 8 ⇒ 2ND ADDEND

Answer:

A which is 6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8

An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How many pounds of the second alloy must be added to the first to get a 12% mixture? 30 lb 40 lb 60 lb

Answers

so, they alloy is hmmm some piece of metal.

it has tin, among other metals, regardless of what other metals it may have, we know that for the first one, 15% is tin, the rest something else, and we also know that the alloy itself, weights 20 lbs.

now, how much is just the weight of the tin metal in it alone? well, is 15% of 20 lbs, or (15/100) * 20, or 3 lbs, so of all those 20 lbs, only 3 lbs or 15% is tin.

for the second alloy, let's say we'll add "x" lbs, we know the second alloy is 10% tin, how much of that weight is tin? well 10% of x, or (10/100) * x, or 0.10x lbs.

now, we're looking for a mixture, say the resulting lbs of mix will be "y" lbs, and we know the mixture will be 12% of tin, how much is 12% of y? (12/100) * y, or 0.12y.

now, regardless of what "x" and "y" is, we know that 20 + x = y, and that 3 + 0.10x = 0.12y, thus

$\bf \begin{array}{lccclll} &\stackrel{lbs}{amount}&\stackrel{tin~\%}{quantity}&\stackrel{tin~lbs}{quantity}\n &------&------&------\n \textit{15\% alloy}&20&0.15&3\n \textit{10\% alloy}&x&0.10&0.10x\n ------&------&------&------\n mixture&y&0.12&0.12y \end{array} \n\n\n \begin{cases} 20+x=\boxed{y}\n 3+0.10x=0.12y\n ----------\n 3+0.10x=0.12\left( \boxed{20+x} \right) \end{cases} \n\n\n 3+0.10x=2.4+0.12x\implies 3-2.4=0.12x-0.10x \n\n\n 0.6=0.02x\implies \cfrac{0.6}{0.02}=x\implies 30=x$

Answer:

30 lb

Step-by-step explanation:

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