Answer:
The time in which the pendulum does a complete revolution is called the period of the pendulum.
Remember that the period of a pendulum is written as:
T = 2*pi*√(L/g)
where:
L = length of the pendulum
pi = 3.14
g = 9.8 m/s^2
Here we know that L = 14.4m
Then the period of the pendulum will be:
T = 2*3.14*√(14.4m/9.8m/s^2) = 7.61s
So one complete oscillation takes 7.61 seconds.
We know that the pendulum starts moving at 8:00 am
We want to know 12:00 noon, which is four hours after the pendulum starts moving.
So, we want to know how many complete oscillations happen in a timelapse of 4 hours.
Each oscillation takes 7.61 seconds.
The total number of oscillations will be the quotient between the total time (4 hours) and the period.
First we need to write both of these in the same units, we know that 1 hour = 3600 seconds
then:
4 hours = 4*(3600 seconds) = 14,400 s
The total number of oscillations in that time frame is:
N = 14,400s/7.61s = 1,892.25
Rounding to the next whole number, we have:
N = 1,892
The pendulum does 1,892 oscillations between 8:00 am and 12:00 noon.
The question involves the concept of a simple pendulum whose number of swings is largely influenced by its length and the acceleration due to gravity. By determining the period of the pendulum, one can figure out the number of oscillations over a given time period. The pendulum's damping constant is negligible in determining the number of oscillations.
The subject of this question involves understanding the concept of a simple pendulum and how it relates to harmonic motion. It is widely known that the mass of the pendulum does not influence the oscillations but rather the length of the pendulum wire and acceleration due to gravity are paramount.
First, the necessary step toward calculating the number of swings would be to calculate the period of the pendulum's oscillation. This is given by the formula T=2*π*sqrt(L/g), where L is the length of the pendulum (14.4m) and g is the acceleration due to gravity (~9.81m/s²). Substituting these values will give us the period, T, in seconds.
The pendulum starts swinging at 8:00 am and at 12:00 noon, 4 hours or 14400 seconds will have passed. Therefore the number of oscillations will be calculated by dividing the total time by one period of oscillation.
It is crucial to note that the damping in this instance is quite small and would not significantly affect the number of oscillations.
#SPJ2
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Answer:
I don't do physics , I'm sorry can't help you
(2) 10^1 m (4) 10^3 m
Considering the definition of percentage by mass, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.
The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.
In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.
The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:
In this case, you know:
Replacing:
Solving:
percent by mass= 6.25 %
Finally, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.
Learn more:
Hello!
What the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?
We have the following data:
m1 (solute mass - iron II sulfate) = 5.0 g
m2 (solvent mass - water) = 75.0 g
m (solution mass) = m1 + m2 = 5.0 + 75.0 = 80.0 g
%m/m (percent mass by mass) = ?
We apply the data to the formula
Answer:
The percent by mass of solute and mass solution of Iron II Sulfate is 6.25%
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