MATHEMATICS HIGH SCHOOL

You have a 10 gallon jug and a 3 gallon jug. Both jugs are unmarked. You need exactly 5 gallons of water. How can you get it if a water faucet is available?

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

You have a 10 gallon jug and a 3 gallon jug and need exactly 5 gallons of water.

This what you do:

- Fill the 3 gallons jug full and pour into the 10 gallons keg

- Repeat the above a second time making a total of 6 gallons of water in the 10 gallons jug.

- Fill the 3 gallons jug a third time and pour into the 10 gallons jug making 9 gallons

- Fill the 3 gallons jug the fourth time and pour into the 10 gallons jug till full leaving 2 gallons of water remaining in the 3 gallons jug.

- Then empty out the 10 gallons jug and pour the 2 gallons of water in the 3 gallons jug into the 10 gallons jug.

- Then, fill the 3 gallons jug again and pour into the 10 gallons jug holding the 2 gallons of water making a total of 5 gallons of water in the 10 gallons jug.

Hope, that helps!!!

Related Questions

If y varies directly with x and x=4 when, y=20, find k, the constant of variation.
Ted weighs twice as much as Julie. Mike weighs three times as much as Julie. Together, Ted, Mike, and Julie weigh 210 lbs. What is the weight of each person?
Help on solving for x
Which function below is the inverse of f(x) = 7x-1/2
Factor : 49c^2 - 25d^6

An astronaut who weighs 126lb on Earth weighs only21lb on the moon. How much would a person who weights 31lb on the moon weigh on Earth?

Answers

If his weight on Earth is 126lb and only 21lb on moon, you can divide $126/21$ to see what is the ratio of those weights.
$126/21=6$

It means that your weight on moon will be 6 times less than on Earth.

Now we have to multiply 31lb which is weight of the person on moon by 6 to get his weight on Earth $6*31=186$

On moon our mass becomes 1/6 of actual mass so if you weigh 60 kg then your mass on moon will be 10 kg..
Similarly if your mass on moon is 31 lbs then your mass on earth will be 31*6=186 lbs.
Please mark it as best if u like it

2,000 water bottles are being labeled and boxed. Each box holds 6 water bottles. How many full boxes can be made?333
334
332
335

Answers

Answer:

Option A.

Step-by-step explanation:

It is given that 2,000 water bottles are being labeled and boxed.

Each box holds 6 water bottles.

Total water bottles = 2000

Water bottles in each box = 6

We need to find the number of full boxes.

So, number of required boxes is

$Boxes=\frac{\text{Total water bottles}}{\text{Water bottles in each box}}$

$Boxes=(2000)/(6)$

$Boxes=333.3333...$

It means 333 full boxes can be made.

Therefore, the correct option is A. `

333 boxes as that will equal 1998 bottles.

Find the range of {(3.2, –3), (7.6, 5.9), (1.4, –3), (–9.1, 8.3)}.

Answers

Answer: The range is the output of our data, in standard notation represented as (x,y) where x is the input and y the output.

So the values of x are the domain, and the values of y are the range.

The set you give is : {(3.2, –3), (7.6, 5.9), (1.4, –3), (–9.1, 8.3)}

You can see that the range is : {-3, 5.9, 8.3}

Notice that in the set, the point y = -3 appears two times (in different pairs), but in the range only one, because you cant repeat the same value in one set.

range is output or y
(x,y)
the range is the 2nd number
when it repeats, don't list again
range=-3,5.9,8.3

hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.

Answers

Answer:

$2√(6)$

Step-by-step explanation:

Perimeter of equilateral triangle = 36 inches

Formula of perimeter of equilateral triangle = $3* side$

⇒ $36=3* side$

⇒ $(36)/(3) = side$

⇒ $12= side$

Thus each side of equilateral triangle is 12 inches

Formula of area of equilateral triangle = $(√(3))/(4) a^(2)$

Where a is the side .

So, area of the given equilateral triangle = $(√(3))/(4) * 12^(2)$

= $36√(3)$

Since hexagon can be divided into six small equilateral triangle .

So, area of each small equilateral triangle = $(36√(3))/(6)$

= $6√(3)$

So, The area of small equilateral triangle :

$(√(3))/(4)a^(2) =6√(3)$

Where a is the side of hexagon .

$(1)/(4)a^(2) =6$

$a^(2) =6* 4$

$a^(2) =24$

$a =√(24)$

$a =2√(6)$

Hence the length of a side of the regular hexagon is $2√(6)$

$Perimter\ of\ equilateral\ triangle\ =36\n a- \ side\ of\ triangle\n 36=3a\ |:3\n a=12\n\n Area\ of\ equilateral\ triangle:\n A=(a^2√(3))/(4)\n A=(12^2√(3))/(4)\n A=(144√(3))/(4)=36\sqrt3 \n\n Hegagon\ can\ be\ divided\ into\ 6\ equilateral\ small\ triangles.\nArea\ of\ one\ of\ them: A_s=(A)/(6)=(36\sqrt3)/(6)=6√(3)\n s-side\ of\ equilateral\ =\ side\ of\ small\ triangle\n A_s=(s^2√(3))/(4)=6√(3)\ |*4 \n s^2\sqrt3=24\sqrt3\ |\sqrt3\n s^2=24\n s=√(24)$ $√(24)=√(4*6)=2\sqrt6\n\n Side\ of\ hexagon\ equals\ 2\sqrt6\ inches$

HELP WITH MY MATH EXAM i don't know what to do and my head hurts a lot

Answers

Answer:

x = 154/13

Step-by-step explanation:

You are given the measures of all three angles in a triangle

so according to the Triangle Sum Theorem:

∠MNO + ∠OMN + ∠NOP = 180

1. Substitute the measures of the angles into the equation:

(3x + 11) + (2x + 20) + (8x - 5) = 180

2. Combine like terms:

(3x + 2x + 8x) + (11 + 20 -5) = 180

13x + 26 = 180

3. Isolate x by subtratcing 26 from both sides

13x + 26 -26 = 180 -26

13x = 154

4. Solve for x by dividing both sides by 13

13x/13 = 154/13

x = 154/13

A customer went to a garden shop and bought some potting soil for $12.50 and 5 shrubs. The total bill was $62.50. Write and solve an equation to find the price of each shrub.A. 5p + $12.50 = $62.50; p = $10.00

B. 5p + $12.50 = $62.50; p = $12.00

C. 5(p + $12.50) = $62.50; p = $7.75

D. 5p + 12.5p = $62.50; p = $3.57