To solve the quadratic equation 4x^2 + 20x = -29 using the quadratic formula, we can first rearrange the equation to bring all terms to one side:
4x^2 + 20x + 29 = 0
Now we can identify the coefficients a = 4, b = 20, and c = 29 in the general quadratic equation ax^2 + bx + c = 0. Applying the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Substituting the values for a, b, and c into the quadratic formula:
x = (-(20) ± √((20)^2 - 4(4)(29))) / (2(4))
Simplifying further:
x = (-20 ± √(400 - 464)) / 8
x = (-20 ± √(-64)) / 8
x = (-20 ± 8i) / 8
Now, we can simplify the expression:
x = -20/8 ± (8i)/8
x = -5/2 ± i
Therefore, the roots of the given quadratic equation are:
x = -5/2 + i
x = -5/2 - i
379.94 in2
452.16 in2
527.52 in2
621.72 in2
Answer:
the Answer is A i just took the test
Answer:
The transformation applied is 'Translation of 1 unit to the right and 2 units downwards'.
Step-by-step explanation:
We know that,
The parent function is .
Now, g(x) is transformed to the function .
That is, we see that,
g(x) is translated 1 unit to the right, which gives and then it is translated 2 unit downwards, which gives f(x).
So, we get,
The transformation applied is 'Translation of 1 unit to the right and 2 units downwards'.
The function ƒ(x) = |x - 1| - 2 has two transformations. It has a horizontal shift to the right by 1 unit and a vertical shift down by 2 units.
The function ƒ(x) = |x - 1| - 2 is a transformation of the basic absolute value function which is |x|. This function is undergoing a shift. Specifically, it is encountering two types of transformation. The |x - 1| part implies the graph of the function is shifted to the right by 1 unit. And the -2 at the end of the function suggests that the graph is shifted downwards by 2 units. Thus, the function ƒ(x) = |x - 1| - 2 illustrates a horizontal shift to the right by 1 unit and a vertical shift downwards by 2 units.
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Answer:
16 = n/12
Step-by-step explanation:
16 = n/12