Whats the perimeter of a regular nonagon with an apothem of 17 cm and a side length of 12.4 cm.

Answers

Answer 1

Answer:

The perimeter of the regular nonagon is 111.6 cm

Step-by-step explanation:

In this question, we are asked to calculate the perimeter of a regular nonagon given the apothem and the length of its side

Since the polygon is regular, it means the length of its sides are equal.

The polygon we are dealing with here is a nonagon meaning it is a 9 sided polygon

Mathematically, the perimeter is ;

P =n * s

where n is the number of sides and a is the length of one of the side of the polygon

From the question, our s = 12.4 cm

Plugging this into the perimeter equation, we have;

P = 12.4 * 9 = 111.6 cm

Related Questions

Solve photo question, please.
Write the equation of a parabola, in standard form, that goes through these points: (0, 3) (1, 4) (-1, -6)
In which quadrant are x and y both negative
Which statement best illustrates using the vertical line test to determine if the graph below is a function of x?The graph is not a function of x because the line x = 0 intersects the graph at two points.The graph is a function of x because the line x = 5 does not intersect the graph.The graph is not a function of x because the line y = 0 intersects the graph at two points.The graph is a function of x because the line y = 5 does not intersect the graph.
I am greater the 4 tens and less then 5 tens.i have 9 ones what am i ?

What are the roots of the polynomial f(x)=x^2+9x-70?

Answers

Roots of the polynomial are values of x when f(x)=0,so
to find the roots of the polynomial we need to solve the equation
x²+9x-70=0 , a=1, b=9,c=-70

$x= \frac{-b+/- \sqrt{ b^(2)-4ac } }{2a}$

$x= (-9+/- √(81+4*1*70) )/(2) = (-9+/- √(361) )/(2)= (-9+/-19)/(2) x_(1)=5, x_(2)=-14$

And the last question is:The sum of two consecutive integers is at least 14. What is the least possible pair of integers?
A) 4 and 5
B) g and 7
C) 7 and 8
D) 8 and 9

Answers

It should be " b " That should be right but u may want to wait for others to respond to this to make sure

I think it is B it cannot be the others!

What is 6 and 3/4 add 1 and 6/7? Write answer as a mixed number thanks! Next Question: What is 9 and 1/5 takeaway 2 and 7/8? Write the answer as a mixed number ok! Next Question : What is 4 and 1/3 times 1 and 3/4 ? Write the answer as a mixed number ok thanks! Last question: What is 6 and 6/7 divided by 3 and 2/3 ? Write the answer as a mixed number!!!!! Ok thanks! Try and answer all the questions ok !!!!!!!!!

Answers

1). 6 3/4+1 6/7

= 27/4 + 13/7

= ((27 × 7) + (13 × 4)) / (4 × 7)

= (189 + 52) / 28

= 241/28

= 241/28

= 8 17/28

2). 9 1/5- 2 7/8

= 46/5 − 23/8

= ((46 × 8) − (23 × 5)) / (5 × 8)

= (368 - 115) / 40

= 253/40

= 253/40

= 6 13/40

3). 4 1/3* 1 3/4

= 13/3 × 7/4

= (13 × 7) / (3 × 4)

= 91/12

= 91/12

= 7 7/12

4). 6 6/7 ÷ 3 2/3

= 48/7 ÷ 11/3

= (48 × 3) / (11 × 7)

= 144/77

= 144/77

= 1 67/77

Hope I helped!

1. $6 (3)/(4)+1 (6)/(7):6+1=7. [tex] (3*7)/(4*7)= (21)/(28) \ and \ (6*4)/(7*4)= (24)/(28) \n$ Add: $(21)/(28)+ (24)/(28)= (45)/(28) \n$ $Answer:\boxed{7 (45)/(28)} \n$ 2. $9 (1)/(5)-2 (7)/(8):9-2=7. [tex] (1*8)/(5*8)= (8)/(40) \ and \ (7*5)/(8*5)= (35)/(40) \n$ Subtract: $(35)/(40)- (8)/(40)= (27)/(40) \n$ Answer: $\boxed{7 (27)/(40)} \n$ 3. $4 (1)/(3)*1 (3)/(4):4*1=4.[tex] (1*4)/(3*4)= (4)/(12) \ and \ (3*3)/(4*3)= (9)/(12) \n$ Cross Multipy: $(4)/(12)* (9)/(12)= (9)/(36) \n$ Simplify:4 \frac{9}{36}=4 \boxed{3}{12}=4 \boxed{1}{4} $\n Answer:\boxed{4 (1)/(4)} \n$ 4. 6 \frac{6}{7}÷3 \frac{2}{3}:6÷3=3. $(6*2)/(7*2)= (12)/(14) \ and \ (3*7)/(2*7)= (21)/(14) \n$ Multiply: $(12)/(14)* (21)/(14)= (252)/(14) \n$ Simplify: $3 (252)/(14)=3 (18)/(1) \n$ Answer: $\boxed{3 (18)/(1)} \n$

WILL ARK BRAINLY!
Evaluate.

5⋅4^0

Answers

Answer:

Step-by-step explanation:

Write a compound inequality that represents the situation. On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour.A. 20 > x > 50

B. 20 ≤ x ≤ 50

C. 20 ≥ x ≥ 50

D. 20 < x < 50

Answers

Answer:

B. 20 ≤ x ≤ 50

Step-by-step explanation:

If the maximum speed is 50 miles per hour, that means it cannot go above 50 miles per hour, it has to be 50 miles per hour or less, which is expressed like this

$x\leq 50$

Now, if the minimum speed is 20 miles per hour, that means the speed can only be 20 miles per hour or more, that's represented as

$x\geq 20$

If we unit both expression, we would have the following compound inequality

$20\leq x\leq 50$

This means that the speed has to be 20 miles per hour or more, but 50 miles per hour or less.

Therefore, the right answer is

The correct answer is b. Hope that helps!

Complete this sentence: After a congruence transformation, the perimeter of a triangle would be _________________ it was before.A. cannot be determined
B. the same as
C. less than
D. greater than

Answers

Congruence transformation results to a perimeter of any polygon that is the same as the original dimensions and shape. In this case, this is similar to translation where all dimensions, angles are retained constant. The answer to this problem hence is B

Answer:the same as

Step-by-step explanation:

Other Questions

How do I solve a problem like -8(n+3)+28=-5n-5

Consider the function f(x)=sin(2x)-1 and g(x)= 2 cos^2(x), both with domain [0,phi]. the line x = p intersects the graph of f in point A and the graph of g in point B. calculate the value of p for which the length of segment AB is maximal. Thank you please kindly answer this question

Given: f(x) = 1/x+5 and g(x) = x-2.What are the restrictions of the domain of f(g(x))?A. X-5B. X=-3C. X = 2D. There are no restrictions.

A real estate agent used the mean and MAD to argue that the home prices of Pepper Hill Road were higher and less variable than those of Cinnamon Court. What is the agent’s error?He should have used the median and IQR because the data is symmetric.its b I just chose randomly He should have used the median and IQR because of the outlier.He should have compared the median and mean.He should have compared the MAD and IQR.