A real estate agent used the mean and MAD to argue that the home prices of Pepper Hill Road were higher and less variable than those of Cinnamon Court. What is the agent’s error?He should have used the median and IQR because the data is symmetric.

its b I just chose randomly
He should have used the median and IQR because of the outlier.

He should have compared the median and mean.

He should have compared the MAD and IQR.

Answers

Answer 1

Answer:

Answer: The agent's error would be B) He should have used the median IQR because of the outlier.

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Please help factor 1/4x^2- 25/9

Answers

$( (1)/(4) {x}^(2) - (25)/(9) ) \n ( (1)/(2) x + (5)/(3) )( (1)/(2)x - (5)/(3) )$

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The range of y = sin(x) is _______. a. 0 ≤ y ≤ 1 b. -1 ≤ y ≤ 1 c. y ≤ 1 d. y ≥ 0

Answers

Answer:

$\sf\nb.\ -1 \le y \le 1$

Explanation:

$\sf\n\textsf{For all real values of x, value of sin(x) will always be greater than or equal to -1 }\n\textsf{and less than or equal to 1.}$

$\textsf{Here is a graph of sine function. From the graph, it is clear that the y-value of sine}\n\textsf{is never above 1 or below -1. So the range of y = sinx is }\sf{-1\le y \le 1.}$

Final answer:

The range of the sin(x) function is -1 ≤ y ≤ 1, because the output of the sin(x) function oscillates between -1 and 1 regardless of the input 'x' value.

Explanation:

The range of a function represents the set of all possible output (y) values that the function can produce. The sine function, sin(x), oscillates between -1 and 1. This is because the maximum height a sine wave can reach is 1 (at π/2 and its equivalents) and its minimal height is -1 (at 3π/2 and its equivalents). Therefore, no matter what value of 'x' you insert into the sin(x) function, the maximum and minimum values for the output 'y' is 1 and -1 respectively. Hence, the correct answer is -1 ≤ y ≤ 1.

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A) Draw a number line from 0 to 2. Then draw and label the points 2 and 0.2. B) use the number line to explain why 2 is 10 times the value of 0.2

Answers

Answer:

See attachment

Step-by-step explanation:

A) We draw the number line as shown in the attachment with intervals of 0.2 from 0 to 2.

B) Observe that, from 0 to 0.2 you move one units to get to 0.2.

From 0 to 2, on the number line with intervals of 0.2, you move 10 units from 0.

This means that:

$2 = 0.2 + 0.2 + 0.2 + 0.2 + 0.2 + 0.2 + 0.2 + 0.2 + 0.2 + 0.2$

This gives us:

$2 = 0.2(1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1)$

Then finally we have:

$2 = 0.2(10)$

By the commutative property of multiplication:

$2 = 10 * 0.2$

A Roast is taken from the refrigerator (where it had been for several days) and placed immediately in a preheated oven to cook. The temperature R = R(t) of the roast t minutes after being placed in the oven is given bya. What is the temperature of the refrigerator?

b. Express the temperature of the roast 30 minutes after being put in the oven in functional notation, and then calculate its value.

c. By how much did the temperature of the roast increase during the first 10 minutes of cooking?

d. By how much did the temperature of the roast increase from the first hour to 10 minutes after the first hour of cooking?

Answers

Answer:

Step-by-step explanation:

a. We are not given enough information to determine the temperature of the refrigerator.

b. We can express the temperature of the roast 30 minutes after being put in the oven as R(30). Its value depends on the specific function R(t) given in the problem.

c. To find the increase in temperature during the first 10 minutes of cooking, we need to find the difference between the temperature of the roast after 10 minutes and the temperature of the roast when it was put in the oven. This is given by:

R(10) - R(0)

d. To find the increase in temperature from the first hour to 10 minutes after the first hour of cooking, we need to find the difference between the temperature of the roast at 1 hour and 10 minutes and the temperature of the roast at 1 hour. This is given by:

R(70) - R(60)

Final answer:

The temperature of the refrigerator is the initial temperature of the roast. The temperature of the roast 30 minutes after being put in the oven can be expressed as R(30), but its value cannot be determined without a specific function. The temperature increase during specific time intervals can be calculated by finding the difference between the temperatures at the respective times.

Explanation:

a. To find the temperature of the refrigerator, we need to use the given information. Since the roast was in the refrigerator for several days before being placed in the oven, we can assume that the temperature of the refrigerator matches the temperature of the roast initially, which is denoted as R(0). Therefore, the temperature of the refrigerator is R(0).

b. Expressing the temperature of the roast 30 minutes after being put in the oven in functional notation is R(30). To calculate its value, we need the specific function or equation that relates the temperature to time. Without this information, we cannot determine the exact numerical value of R(30).

c. To determine the temperature increase during the first 10 minutes of cooking, we need the temperature difference between the initial temperature of the roast (R(0)) and the temperature after 10 minutes of cooking (R(10)). The increase is given by R(10) - R(0).

d. To find the temperature increase from the first hour to 10 minutes after the first hour of cooking, we need the temperature at the start of the first hour (R(60)) and the temperature at 10 minutes after the first hour (R(60 + 10)). The increase is given by R(60 + 10) - R(60).

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I need help with number 19 please!

Answers

Answer:

center: (4, 3)
radius: 5

Step-by-step explanation:

A graphing calculator can help you see the center is (4, 3) and the diameter is 10, so the radius is 5.

_____

Or, you can rearrange the equation to standard form by completing the squares.

x² -8x + y² -6y = 0 . . . . . subtract 6y, group terms

(x² -8x +16) +(y² -6y +9) = 16 +9 . . . . . complete the squares by adding the squares of half the coefficient of the linear term: (-8/2)²=16, (-6/2)²=9.

(x -4)² + (y -3)² = 25 . . . . . rewrite in standard form

Compare this to ...

(x -h)² + (y -k)² = r²

and recognize the center (h, k) is (4, 3), and the radius is √25 = 5.

Find the slope and y-intercept of the line
x+2y=6

Answers

x+2y=6

-x -x

2y = -x + 6

y = -1/2x + 3

The slope is -1/2 and y-int is 3

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