WILL GIVE BRAINLIEST!!!! Nonpolarized light of intensity Io is incident on a polarizing filter, and the emerging light strikes a second polarizing filter. What is the light intensity emerging from the second polarizing filter?
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Answer:
50% of unpolarised light passes through the first filter because, on average, 50% of the waves are aligned with the fiter's axis. Intensity is reduced by a factor 0.5.
The second filter then reduces the intensity by a factor cos²(θ)
Explanation:
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What is big and green with horns and jumps high?
The relationship between a cathode and an anode involvesA. protons.B. diodes.C. electrons.D. neutrons.
A freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour. Give the original speed of the train. a. 20 miles/hour b. 25 miles/hour c. 30 miles/hour d. 35 miles/hour
What is the purpose of using the Scientific Method? Select all that apply.
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Answer:
a) 8*10^-8C/m²
b) +9.04*10^3N/C
c) = -9.04*10^3N/C
Explanation:
Given
Side length, L = 50cm = 0.5m
Charge on the plate, Q = 4*10^-8C
Surface charge density, σ = Q/A
The surface charge density of each part is then half of the total charge density of the plate. Thus,
σ(face) = 1/2σ
σ(face) = Q/2A
σ(face) = Q/2L²
Now we plug in, since we have Q and L
σ(face) = 4*10^-8 / 2*0.5²
σ(face) = 4*10^-8 / 0.5
σ(face) = 8*10^-8C/m²
Magnitude of electric field above the plate is,
E = σ(face) / E•
E = 8*10^-8 / 8.85*10^-12
E = 9.04*10^3 N/C
If we assume this plate lies on the side of the "xy" plane, the electric field is directed in the positive "z" direction. As such,
E = +9.04*10^3N/C
Electric field below the plate has the same magnitude, but different direction. So, E = -9.04*10^3N/C
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From your equation, we can tell that you're defining the upward direction as
positive. We can also tell that you threw the stone upward, with an initial speed
as it left your hand of 128 feet per second, about 87 miles per hour ... a mighty toss indeed, and I think there's a man from the Chicago Cubs waiting outside
who'd like to talk to you.
Anyway, When the stone splashes into the water, h(t) = 0 .
-16t² + 128t + 32 = 0
Divide each side by -16 :
t² - 8t - 2 = 0
I don't see any easy way to factor the expression on the left,
so I have to use the quadratic formula to solve this equation.
t = 4 plus and minus √18 .
t = +8.24 seconds
t = -0.24 second
Mathematically, both numbers are valid solutions.But when you apply
the equation to a real world situation, only the positive 't' makes sense.
So t = 8.24 seconds.
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Particles of matter are packed more tightly in the ground than in the air.
Air doesn’t contain any particles of matter to transmit sound waves.
The elevation of the ground is lower than the elevation of the air space.
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Answer:
Particles of matter are packed more tightly in the ground than in the air.
Explanation:
As we know that velocity of sound in a given medium is given by formula
here we know that
E = elasticity of the medium
= density of the medium
now we know that if we increase the density of medium then particles of matter are packed more which will decrease the speed of wave.
while is particles are tightly packed then it will increase the elasticity of the medium
So here if all particles are tightly bounded with each other then sound waves will move faster through the medium
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Given v_in = 20 m/s and a = 3 m/s2, assuming that the bodymoves at constant acceleration, the motion is modeled by the equation:
s(t) = (v_in)t + (1/2)a(t^2)
where s(t) is the distance traveled
substituting the given,
s(t) = 20t + (3/2)(t^2)
at t = 3
s(t) = 20(3) + (3/2)(3)^2
= 73.5 m
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Potential energy is gained here as he swings.