Pick an image of two triangles placed as directed pls a b c pick for 1) and 2)

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Answer 1

Answer:

Step-by-step explanation:

When the given two triangles would be joined they will form the image as given in option B

Name of the quadrilateral would be: (A) rectangle

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In an effort to make children’s toys safer and more tamperproof, toy packaging has become cumbersome for parents to remove in many cases. Accordingly, the director of marketing at Toys4Tots, a large toy manufacturer, wants to evaluate the effectiveness of a new packaging design that engineers claim will reduce customer complaints by more than 10 percentage points. Customer satisfaction surveys were sent to 220 parents who registered toys packaged under the old design and 220 parents who registered toys packaged under the new design. Of these, 81 parents expressed dissatisfaction with packaging of the old design, and 41 parents expressed dissatisfaction with packaging of the new design.What's the T-Statistic
I’m really struggling, someone please help!
Miguel has a jar full of dimes and quarters. There are a total of 115 coins with a total value of$17.05. The system of equations that represents this situation is as follows: d + q =115 and10d + 25 = 1705 How many MORE dimes than quarters are in Miguel's jar?
SOMONE HELP WITH MATH
Πr2/2 for a half circle Half circle: 1.5 in

Please help it’s due at 5

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Answer:

nei prossimi giorni, che si è svolto il convegno

There are 7 bananas, 10 oranges, and 5 apples and 5 apples in the fruit bowl. What is the ratio of bananas to fruit?

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Answer:

5:27

Step-by-step explanation:

In the box below, enter the value that is missing from the table.

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Answer:

the value that is missing from the table is 8.

Answer: 8

Step-by-step explanation:

Which equation is equivalent to 4 x = t + 2
s = t-2
s=4/t+2
s=t+2/4
s=t+6

Answers

B= S=4/t+2
whenever you have the equation 4 x = t+2 you are trying to isolate the X by doing that you have ti take the 4 and divide it to the other side so the x can stay on that side

6.Write the equation in slope-intercept form for the line that passes through the given pointand is perpendicular to the given equation.5x + 3y = -21 and passes through (-5, 1)

Answers

Let us first solve for the slope (m) of the perpendicular line.

$\text{ 5x + 3y = -21}$ $\text{ 3y = -5x - 21}$ $\text{ y =}\frac{-5x\text{ -21}}{3}$ $\text{ y = -}(5)/(3)x-7$

The slope of the perpendicular line is -5/3.

Thus, for the slope of the line, we get,

$\text{ m}_(\perp)\text{ = }(-5)/(3)$ $\text{ m = }(3)/(5)$

Let us solve for the value of b with the given value of slope (m) = 3/5 and (x,y) = (-5,1).

$\text{ y = mx + b}$ $1\text{ = (}(3)/(5))(-5)+b$ $1\text{ = -1 + b ; b = 1 + 1 = }2$

Let's now make the equation of the line using Slope-Intercept Form,

Given, m = 3/5 and b = 2

$\text{ y = mx+b}$ $\text{ y = (}(3)/(5))x\text{ + 2}$

$\text{ y = }(3)/(5)x\text{ +2}$

A true/false test has 90 questions. Suppose a passing grade is 58 or more correct answers. Test the claim that a student knows more than half of the answers and is not just guessing. Assume the student gets 58 answers correct out of 90. Use a significance level of 0.05. Steps 1 and 2 of a hypothesis test procedure are given below. Show step 3, finding the test statistic and the p-value and step 4, interpreting the results.

Answers

Answer:

1 and 2) Null hypothesis: $p \leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{(p_o (1-p_o))/(n)}}$ (1)

3) $z=\frac{0.644 -0.5}{\sqrt{(0.5(1-0.5))/(90)}}=2.732$

4) $p_v =P(z>2.732)=0.0031$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v<\alpha$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of correct answers is not significantly higher than 0.5

Step-by-step explanation:

Data given and notation

n=90 represent the random sample taken

X=58 represent the number of correct answers

$\hat p=(58)/(90)=0.644$ estimated proportion of correct answers

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Step 1 and 2: Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of correct answers is higher than 0.5.:

Null hypothesis: $p \leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{(p_o (1-p_o))/(n)}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.644 -0.5}{\sqrt{(0.5(1-0.5))/(90)}}=2.732$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.732)=0.0031$

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: the number of correct answers on a true/false test out of 90 questions.

The parameter of interest is p: population proportion of correct answers in a true/false test.

The passing grade is 58/90 correct questions.

The claim is that if the students answer more than half of the answers, then he is not guessing, i.e. if the proportion of correct answers is more than 50%, the student did not guess the answers, symbolically: p>0.5

Then the hypotheses are:

H₀: p ≤ 0.5

H₁: p > 0.5

α: 0.05

since the sample size is large enough, n= 90 questions, you can apply the Central Limit Theorem to approximate the distribution of the sample proportion to normal, p'≈N(p;[p(1-p])/n) and use the standard normal as a statistic:

$Z=\frac{p'-p}{\sqrt{(p(1-p))/(n) } }$ ≈N(0;1)

The sample proportion is the passing grade of the student p': 58/90= 0.64

Then under the null hypothesis the statistic is:

$Z_(H_0)= \frac{0.64-0.5}{\sqrt{(0.5*0.5)/(90) } } = 2.656= 2.66$

This test is one-tailed (right) and so is the p-value, you can calculate it as:

P(Z≥2.66)= 1 - P(Z<2.66)= 1 - 0.996093= 0.003907

With this p-value, the decision is to reject the null hypothesis.

Then at a 5% level, there is significant evidence to conclude that the proportion of correctly answered questions is greater than 50%, this means that the student didn't guess the answers.

I hope this helps!

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ind the area of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximations).

Name the slope and one point that is on the linerepresented by the equation: x = -2A) m = undefined and point (-2,5)B) m = 0 and point (-2,4)C) m = undefined and point (5,-2)D) = zero and point (5,0)

The other answer choice is 30