ind the area of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximations).
Answers
First find the area of the circle
Area = πr^2
=3.14 x 16
50.24 cm^2
But here we need the area of the semicircle
so 50.24/2 = 25.12 cm^2
Now we find the area of the triangle
Area = 1/2bh
= 1/2 x 8 x 4
16 cm^2
The area of the shaded region = 25.12-16
= 9.12 cm^2
Hope this helps you!
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There are 25 marbles in the box. There are 10 red marbles , 8 blue marbles , and 7 yellow marbles . What percent of the marbles are NOT yellow ?A. 28%B. 72%C. 32%D. 40%
Answers
9514 1404 393
Answer:
y = 55°
Step-by-step explanation:
You know the sum of angles in a triangle is 180°. So, ...
25° +30° +x = 180°
And, you know a linear pair of angles totals 180°:
x + y = 180°
Substituting for 180°, we have ...
25° +30° +x = x + y
Subtracting x from both sides, we get a relation that is useful to remember:
25° +30° = y
y = 55°
_____
This relation is usually described as ...
An exterior angle is equal to the sum of the remote interior angles.
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Answers
Answers
Answer:
1. p*(1-p)
2. n*p*(1-p)
3. p*(1-p)
4. 0
5. p^2*(1-p)^2
6. 57/64
Step-by-step explanation:
1. Let Ik denote the reward (possibly 0) given at time k, for k∈{1,2,…,n}. Find E[Ik].
E[Ik]= p*(1-p)
2. Using the answer to part 1, find E[R].
E[R]= n*p*(1-p)
The variance calculation is more involved because the random variables I1,I2,…,In are not independent. We begin by computing the following values.
3. If k∈{1,2,…,n}, then
E[I2k]= p*(1-p)
4. If k∈{1,2,…,n−1}, then
E[IkIk+1]= 0
5. If k≥1, ℓ≥2, and k+ℓ≤n, then
E[IkIk+ℓ]= p^2*(1-p)^2
6. Using the results above, calculate the numerical value of var(R) assuming that p=3/4, n=10.
var(R)= 57/64
and mZTRB = 86. Find the mZTRI.
Answers
Answer:
m∠TRI = 43
Step-by-step explanation:
m∠TRI + m∠IRB = m∠TRB
3x - 5 + x + 27 = 86
3x + x - 5 + 27 = 86 {Combine like terms}
4x + 22 = 86 {Subtract 22 from both sides}
4x = 86 - 22
4x = 64 {Divide both sides by 4}
x = 64/4
x = 16
m∠TRI = 3x - 5
= 3*16 - 5
= 48 - 5
= 43